Question

A 12.0g sample of a substance requires 50.9 J to raise its temperature by 6.00 c. What is it’s specific heat

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's find the specific heat of sample using given formula :

$\qquad \tt \dashrightarrow \:Q = m \: s \triangle T$

where,

• Q = heat transfer

• m = mass

• S = specific heat

• $\tt \triangle T$ = change in temperature

$\qquad \tt \dashrightarrow \:50.9 = 12 \times \: s \times 6$

$\qquad \tt \dashrightarrow \:s = \dfrac{50.9}{72}$

$\qquad \tt \dashrightarrow \:s = 0.707 \:$

Therefore, specific heat of that substance is 0.707 J/g°C