Answer:
The answer is b, c, d, e
Explanation:
b. 2 N2O5 → 4 NO2 + O2
r = k [N2O5]^2 --> Second-order regarding global reaction
c. 2 HI → H2 + I2
r = k [HI]^2 --> Second-order regarding global reaction
d. 2 N2O → 2 N2 + O2
r = k [N2O]^2 --> Second-order regarding global reaction
e. 2 NO2 → 2 NO + O2
r = k [NO2]^2 --> Second-order regarding global reaction
Answer:
low-spin complexes contain the maximum number of unpaired electrons.
Explanation:
In the crystal field theory, the magnitude of crystal field splitting and the pairing energy determines whether a complex will be low spin or high spin.
Low spin complexes often have greater magnitude of crystal field splitting energy than low spin complexes.
High spin complexes have maximum number of unpaired electrons(most of the electrons are unpaired) while low spin complexes have a minimum number of unpaired electrons in a complex(most of the electrons are paired).
Answer: Malleability
Explanation: cuz ... its right ... lol
