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OlgaM077 [116]
3 years ago
11

How can you determine the relationship between corresponding terms? Give an example.

Mathematics
1 answer:
stellarik [79]3 years ago
3 0
You have to try to determine the sequence, and you try two basic kind of sequences: aritymethic and geometric.

In aritmetic sequeces the relationships is that the difference between any adjacent terms is constant.

For example

´Number of term (n)     Term, An

1                                   7

2                                   11

3                                   15

4                                   19

Then the relationship between adjacent terms is 19 - 15 = 4 = 15 -11 = 4 = 11 - 7 = 4.

You can find, then, a general expression that relates any term with its position.

It is An = 7 + (n-1)*4

In geometric sequences the relationship is found dividing two adjacent terms, because the ratio is constant.

For example:

Number of term     Term

1                            10
2                            20
3                            40
4                            80

You can then find the relation as: 20/10 = 2 = 40/20 = 2 = 80/40 = 2.

In this case the general term is An = 10 * 2^ (n-1) 
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1/9 is a fraction, so it is rational.

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With a little care, you can find the median and the quartiles from the histogram. what are these numbers? you can also find the
coldgirl [10]

Complete Question

The histogram from this question is shown on the first uploaded image

Answer:

The first quartile is  1st Q = 19^{th} girl (subject ) = 1 \serving\ of\ fruit\ per\ day

The median is   Median  = 38 ^{th} \ girl (subject) =  2 \serving\ of\ fruit\ per\ day

The third quartile  is 3rd Q =  56^{th} \  girl (subject) = 4 \serving\ of\ fruit\ per\ day  

The  mean is  \= x = 2.62

Step-by-step explanation:

From the question we are told that

   The total  number of girls is n =  74

Generally the median is mathematically represented as

       Median  =  \frac{\frac{n}{2}  +[ \frac{n}{2} + 1]  }{2}

So

          Median  =  \frac{\frac{74}{2}  +[ \frac{74}{2} + 1]  }{2}

=>         Median  =  \frac{37  +38 }{2}

=>         Median  =37.5 \  girl    

From the histogram 37.5 \approx 38^{th} \ girl fall under 2 fruits per day

Generally the first quartile is mathematically represented as

      1st \ Q =  \frac{\frac{n}{4} + [\frac{n}{4} + 1]  }{2}

=>    1st \ Q =  \frac{\frac{74}{4} + [\frac{74}{4} + 1]  }{2}

=>     1st \ Q = 19 \  girl

From the histogram 19^{th}girl fall under 1 fruit per day

 Generally the third quartile is mathematically represented as

     3rd\  Q =  \frac{\frac{n}{2}  + n }{2}

=>    3rd\  Q =  \frac{\frac{74}{2}  + 74 }{2}

=>    3rd\  Q =  55.5

From the histogram 55.5 \approx 56^{th} \ girl fall under 4 fruits per day

Generally from the histogram table the frequency  [number of subjects (girls) ]  and the servings of fruit per day can be represented as

                                                                                                               Total

x(servings per day )        0     1     2     3     4     5    6     7      8    

f (number of subjects )   15    11   15     11    8     5    3     3      3    \sum f  =  74

xf                                       0    11    30   33   32  25   18   21     24    \sum xf =  194

Generally the mean is mathematically represented as

      \= x = \frac{1}{ \sum f}  * [\sum xf]

=>     \= x = \frac{1}{ 74}  *194

=>      \= x = 2.62

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Answer:

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950 divided by 19 is 50.

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