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ki77a [65]
2 years ago
6

If the north pole of one magnetic is brought near the south pole of another magnet, the poles will

Physics
1 answer:
Levart [38]2 years ago
6 0

Answer: Heyo Kenji Here! Here's your answer-If the north pole of a magnet is brought near the south pole of another magnet, they will get attracted towards each other.

Explanation: Hope this helps!

Have a nice day!

- Kenji ^^

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A plane travels 1743 KM in 2 hours 30 minutes. How fast was the plane traveling?
Advocard [28]

Answer:

v=697.2km/h

Explanation:

Hello.

In this case, since the velocity is computed via the division of the distance traveled by the elapsed time:

V=\frac{d}{t}

The distance is clearly 1743 km and the time is:

t=2h+30min*\frac{1h}{60min} =2.5h

Thus, the velocity turns out:

v=\frac{1743km}{2.5h}\\ \\v=697.2km/h

Which is a typical velocity for a plane to allow it be stable when flying.

Best regards.

5 0
3 years ago
Calculate the heat energy released when 13.3 g of liquid mercury at 25.00 C is converted to solid mercury at its melting point.C
dmitriy555 [2]

Answer:

-270.321012\ J

Explanation:

C_v = Heat capacity of Hg = 28 J/mol

\Delta T = Change in temperature = (234.32-(273.15+25))

\Delta H_{f} = Enthalpy of fusion = 2.29 kJ/mol

The number of moles is given by

n=13.3\times \dfrac{1}{200.59}\\\Rightarrow n=0.0663\ molHg

Heat is given by

Q_1=nC_v\Delta T\\\Rightarrow Q_1=0.0663\times 28\times (234.32-(273.15+25))\\\Rightarrow Q_1=-118.494012\ J

Heat released is given by

Q_2=-n\Delta H_{f}\\\Rightarrow Q_2=-0.0663\times 2.29\times 10^3\\\Rightarrow Q_2=-151.827\ J

Total heat is given by

Q=Q_1+Q_2\\\Rightarrow Q=-118.494012+(-151.827)\\\Rightarrow Q=-270.321012\ J

The total heat released is -270.321012\ J

4 0
3 years ago
A small 13.0-g bug stands at one end of a thin uniform bar that is initially at rest on a smooth horizontal table. The other end
OLEGan [10]

Answer:

cnbvhgdsjbgfvvfs

Explanation:

wefrwdfvbgregfwdfewrfd

4 0
3 years ago
A 2 kg body is dropped from a height of 3 m. Calculate:
NikAS [45]

Answer:

   a) 6.26 m/s

   b) 7.67 m/s

Explanation:

The potential energy at height h0 is initially ...

  PE0 = mgh0

At height h1, the potential energy is ...

  PE1 = mgh1

The difference in potential energy is converted to kinetic energy:

  PE0 -PE1 = KE1 = (1/2)m(v1)^2

Solving for v1, we have ...

  mg(h0 -h1) = (1/2)m(v1)^2

  2g(h0 -h1) = (v1)^2

  v1 = √(2g(h0 -h1))

__

a) When the body is 1 m high, its speed is ...

  v = √(2(9.8)(3 -1)) ≈ 6.26 m/s . . . at 1 m high

__

b) When the body is 0 m high, its speed is ...

  v = √(2(9.8)(3 -0)) ≈ 7.67 m/s . . . when it reaches the ground

3 0
3 years ago
Which of the following is an accurate statement?
weeeeeb [17]

An object's momentum will change if there is a non-zero net external force acting on it. This assertion is true.

<h3></h3><h3>What is momentum?</h3>

The momentum is defined as the product of mass and the velocity of the body. It is denoted by the letter P. It occurs due to the applied force. Its unit is Kg m/s².

p=mΔV

If there is a change in the velocity there must be a force acting on the object.

If an object is acted on by a non-zero net external force, its momentum will not remain constant. is an accurate statement.

<h3></h3>

Hence, option B is correct.

To learn more about the momentum refer to the link;

brainly.com/question/4956182

#SPJ1

7 0
2 years ago
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