Please help 10pts each
2 answers:
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Answer:
16.7%
Step-by-step explanation:
Please check below attachment for sample space table
Firstly, we have the total number of possible results as 12
From the 12, the probability of flipping a head is 6/12
Rolling either a 3 or a 5 is the sum of places we have both divided by the possible total of 12
we have this as ; 2/12 + 2/12 = 4/12
The term ‘AND’ means we have to multiply the two probabilities as follows;
4/12 * 1/2 = 1/6 = 0.1667
To the nearest tenth, we have this as 16.67% which is 16.7%
Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
