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vichka [17]
2 years ago
9

After a dilation with center (0,0) the image of DB is D’B’ if DB=6 and D’B’=2 the scale factor of dilation is what ?

Mathematics
1 answer:
bezimeni [28]2 years ago
7 0

Answer:

scale factor = \frac{1}{3}

Step-by-step explanation:

the scale factor is the ratio of corrresponding sides. image to original.

scale factor = \frac{D'B'}{DB} = \frac{2}{6} = \frac{1}{3}

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The GCF of the numbers in the expression (55 + 44) is _____. The numbers left inside the parentheses after factoring out the GCF
Alenkinab [10]
55=5*11
44=4*11
gcf=11

11(5)+11(4)=11(5+4)

the numbers inside are 5 and 4


<span>The GCF of the numbers in the expression (55 + 44) is <u>11</u>. The numbers left inside the parentheses after factoring out the GCF are <u>5</u> and <u>4</u>. </span>



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3 years ago
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3 years ago
While working at the drugstore, kyle earns $15 per hour. how many hours will it take to earn $45
Furkat [3]

Answer:

3

Step-by-step explanation:

15+15+15=45 or you can just do 15x3

7 0
3 years ago
A police helicopter is flying at 150 mph at a constant altitude of 0.5 mile above a straight road. The pilot uses radar to deter
natali 33 [55]

Answer:

a) (see attached picture)

b) d, h, velocity of helicopter, dd/dt

in the direction oposite to the movement of the helicopter.

Step-by-step explanation:

In order to solve this problem we must start by drawing a diagram that will represent the situation (see attached picture). As you may see, there is a right triangle being formed by the helicopter, the car and the graound. We can use this to build the equation we are going to use to model the problem.

d^{2}=h^{2}+x^{2}

we can use this equation to find the value of x at that very time, so we can do that by solving the equation for x, so we get:

x=\sqrt{d^{2}-h^{2}}

and substitute the given values:

x=\sqrt{(1)^{2}-(0.5)^{2}}

which yields:

x=0.866mi

we know that the height of the helicopter is going to be constant, so we rewrite the equation as:

d^{2}=(0.5)^{2}+x^{2}

d^{2}=0.25+x^{2}

Next, we can go ahead and differentiate the equation so we get:

2d\frac{dd}{dt}=2x\frac{dx}{dt}

which can be simplified to:

d\frac{dd}{dt}=x\frac{dx}{dt}

we can next solve the equation for dx/dt so we get:

\frac{dx}{dt}=\frac{d}{x}*\frac{dd}{dt}

so we can now substitue te provided values so we get:

\frac{dx}{dt}=\frac{1}{0.866}*-190

so we get:

\frac{dx}{dt}=-219.40mph

the negative sign means that the x-value is decreasing.

now, this problem deals with relative velocities, so we get that:

Velocity of car about the helicopter = Velocity of the car - Velocity of the helicopter. Or:

V_{ch}=V_{c}-V_{h}

so we can solve this for the actual velocity of the car, so we get:

V_{c}=V_{ch}+V_{h}

so we get:

V_{c}=-219.40mph+150mph

which yields:

V_{c}=-69.4mph

So it has a velocity of 69.4mph in a direction oposite to the helicopter's movement.

4 0
3 years ago
Forty one people were riding bus number 527. At 8:45 am,it arrived at the 109th street stop. There,19 people got off and then 20
agasfer [191]

Answer:

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5 0
3 years ago
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