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anygoal [31]
3 years ago
15

Under Juran's Law, whenever a problem occurs, what percentage of the time is the problem the result of a system/process error?

Computers and Technology
1 answer:
quester [9]3 years ago
7 0

Answer:

C. 85 percent

Explanation:

Juran's Law is a law used in the category of Total Quality Management. This law states that whenever a problem occurs during a process, only about 15% of the time is it the individual's fault, the rest of the time it is the process's fault. Therefore 85% of the time, the problem is the result of a system/process error.

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For this lab you will do 2 things:
zepelin [54]

Answer:

Here is the Python program:

COOKIES_PER_BAG = 40 #sets constant value for bag of cookies

SERVINGS_PER_BAG = 10 #sets constant value for serving in bag

CALORIES_PER_SERVING = 300 #sets constant value servings per bag

cookies = int(input("How many cookies did you eat? ")) #prompts user to input how many cookies he or she ate

totalCalories = cookies * (CALORIES_PER_SERVING / (COOKIES_PER_BAG / SERVINGS_PER_BAG)); #computes total calories consumed by user

print("Total calories consumed:",totalCalories) #displays the computed value of totalCalories consumed

Explanation:

The algorithm is:

  • Start
  • Declare constants COOKIES_PER_BAG, SERVINGS_PER_BAG and CALORIES_PER_SERVING
  • Set COOKIES_PER_BAG to 40
  • Set SERVINGS_PER_BAG to 10
  • Set CALORIES_PER_SERVING to 300
  • Input cookies
  • Calculate totalCalories:                                                                                                                       totalCalories ← cookies * (CALORIES_PER_SERVING / (COOKIES_PER_BAG / SERVINGS_PER_BAG))
  • Display totalCalories

I will explain the program with an example:

Lets say user enters 5 as cookies he or she ate so

cookies = 5

Now total calories are computed as:

totalCalories = cookies * (CALORIES_PER_SERVING / (COOKIES_PER_BAG / SERVINGS_PER_BAG));  

This becomes:

totalCalories = 5 * (300/40/10)

totalCalories = 5 * (300/4)

totalCalories = 5 * 75

totalCalories = 375

The screenshot of program along with its output is attached.

4 0
4 years ago
IDENTIFYING VERBS THAT AGREE IN NUMBER WITH THEIR SUBJECTS For each of the following sentences, write the correct form of the ve
Novay_Z [31]

Hey there!

  • The word "<u>verb</u>" simply means <em>'description of an action, assert, or event that is made into the main purpose of your predicate in your judgement' </em>
  • Now that we have the definition of the word verb we can answer your question
  • "<em>Has</em>" is past tense but it is THIRD person present
  • "<em>Have</em>" is when you own something
<h2>Answer: HAS ✅</h2>

BECAUSE "I SAW last night"

Note: usually people read the sentence to themselves until it makes easier sense to them or use context clues in the sentence to answer the particular question(s)

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

6 0
3 years ago
Read 2 more answers
Draw a timeline for each of the following scheduling algorithms. (It may be helpful to first compute a start and finish time for
12345 [234]

Answer:

See explanation below

Explanation:

Previos concepts

First Come First Serve (FCFS) "is an operating system scheduling algorithm that automatically executes queued requests and processes in order of their arrival".

Shortest job next (SJN), or the shortest job first (SJF) or shortest "is a scheduling policy that selects for execution the waiting process with the smallest execution time".

Shortest remaining time (SRF) "is a scheduling method that is a preemptive version of shortest job next scheduling'".

Round robin (RR) is an algorithm where the time parts "are assigned to each process in equal portions and in circular order, handling all processes without priority"

Solution for the problem

Assuming the dataset given on the plot attached.

Part a

For this algorithm the result would be:

Job A   0-6

Job B   6-(6+3) = 6-9

Job C   9-(9+1) = 9-10

Job D   10-(10+4) = 10-14

Part b

For this algorithm the result would be:

Job A   0-6

Job C   6-(6+1) = 6-7

Job B   7-(7+3) = 7-10

Job D   10-(10+4) = 10-14

Part c

For this algorithm the result would be:

Job A   0-1  until 14

Job B   2-(2+3) = 2-5

Job C   3-(3+2) = 3-5

Job D   9-(9+5) = 9-14

Part d

For this algorithm the result would be:

Job A   0-2 , 7-9, 12-14

Job B   2-4, 9-10

Job C   4-(4+1) = 4-5

Job D   5-7, 10-12

8 0
3 years ago
How do you activate a sim card in an HP probook 6470b and what drivers are needed​
UNO [17]

[YOU NEED A SIM CARD TRAY, IF A DRIVER IS NEEDED IT WILL TELL YOU AND JUST LET YOU INSTALL IT]

-Ensure the device is powered off.

-From the left edge of the device, remove the card tray. ...

-With the gold contacts facing down and the notch located in the lower-right, insert the SIM card into the tray as shown. ...

-Insert the card tray.

8 0
3 years ago
Write a C program to prform simple C aritlimetic calculations. The user is to enter a simple expression(integer operaior integer
larisa86 [58]

Answer:

Here is the C program:

#include <stdio.h>  //to use input output functions

//functions prototype

unsigned int mod(unsigned int a, unsigned int b);  

unsigned int mul(unsigned int a, unsigned int b);  

unsigned int sub( unsigned int a,unsigned int b);

float divide(unsigned int a,unsigned int b);  

unsigned int add( unsigned int a,unsigned int b);  

int main()  {  //start of main method

unsigned int a, b;   //declare variables to store the operands

char d;  //declare variable to store the operator

printf("Enter an operator:  ");   //prompts user to enter an operator

scanf("%c",&d);  //reads the operator from use

getchar();  //gets a character

while (d!='q')   { //keeps iterating until user enters q to quit

printf("Enter 1st operand: ");   //prompts user to enter first operand

scanf("%d",&a);   //reads first operand from user

getchar();  //reads character

printf("Enter 2nd operand: ");   //prompts user to enter second operand

scanf("%d",&b);   //reads second operand from user

getchar();  

if (d=='%')  {   //if the character of operator is a mod

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

mod(a,b);  }  //displays computed modulo of two input operands

if (d=='*')   //if the input character is for multiplication operator

{printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

mul(a,b); }  //displays computed multiplication

if (d=='+')  {  //if the input character is for addition operator

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = "); // displays =

add(a,b);  }   //displays computed addition

if (d=='/')  {  //if the input character is for division operator

printf("%d",a); // prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

divide(a,b);  }   //displays computed division

if (d=='-')  {  //if the input character is for subtraction operator

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b); // displays operand 2

printf(" = ");  //displays =

sub(a,b);  }  //displays computed subtraction

printf("Enter an operator: ");   //asks again to enter an operator

scanf("%c",&d);  //reads operator from user

getchar();  }  }   //gets character

unsigned int mod( unsigned int a, unsigned int b){  //function to compute modulo of two integers with no sign

     int c = a%b;  //computes mod

    printf("%d",c);  }  //displays mod result

unsigned int add(unsigned int a, unsigned int b){     // function to compute addition of two integers

    int c = a+b; //computes addition

    printf("%d\n",c);  } //displays result of addition

unsigned int mul(unsigned int a, unsigned int b){       //function to compute multiplication of two integers

    int c = a*b;  //multiplies two integers

   printf("%d\n",c); }  //displays result of multiplication

float divide(unsigned int a, unsigned int b){   //function to compute division of two integers

    float c = a/b;  //divides two integers and stores result in floating point variable c

    printf("%f\n",c);  } //displays result of division

unsigned int sub(unsigned int a, unsigned int b){       //function to compute subtraction of two integers

    int c = a-b;  //subtracts two integers

    printf("%d\n",c);  }  //displays result of subtraction

Explanation:

The program is well explained in the comments mentioned with each line of the program. The program uses while loop that keeps asking user to select an operator and two operands to perform arithmetic calculations. The if conditions are used to check what arithmetic calculation is to be performed based on user choice of operand and calls the relevant function to perform calculation. There are five functions that perform addition, modulo, subtraction, division and multiplication and display the result of computation. The screenshot of output is attached.

4 0
3 years ago
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