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ZanzabumX [31]
2 years ago
13

Help guys I realy need help I will report you if you give me the wrong answer

Mathematics
1 answer:
telo118 [61]2 years ago
7 0

Answer:

the Answer is 150x + 12100 ≤ 26500

Step-by-step explanation:

The max weight is 26500 so the weight would have to be the same or less than 26500 (≤)

There is already 12100 killograms on the sipping containter so that is why you have + 12100

and you have 150x because x is the number of 150-kilogram crates

and for as many crates you have to multiply by the weight.

You might be interested in
Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e
svet-max [94.6K]

ANSWER

y = 2x -4

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

x = 5 +  ln(t)

y =  {t}^{2}  + 5

From the first equation we make t the subject to get;

x - 5 =  ln(t)

t =  {e}^{x - 5}

We put it into the second equation.

y =  { ({e}^{x - 5}) }^{2}  + 5

y =  { ({e}^{2(x - 5)}) }  + 5

We differentiate to get;

\frac{dy}{dx}  = 2 {e}^{2(x - 5)}

At x=5,

\frac{dy}{dx}  = 2 {e}^{2(5 - 5)}

\frac{dy}{dx}  = 2 {e}^{0}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5)

y = 2x - 10 + 6

y = 2x -4

Without eliminating the parameter,

\frac{dy}{dx}  =  \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }

\frac{dy}{dx}  =  \frac{ 2t}{  \frac{1}{t} }

\frac{dy}{dx}  =  2 {t}^{2}

At x=5,

5 = 5 +  ln(t)

ln(t)  = 0

t =  {e}^{0}  = 1

This implies that,

\frac{dy}{dx}  =  2 {(1)}^{2}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5) =

y = 2x -4

5 0
3 years ago
Examine the following expression.
svetoff [14.1K]

Answer:

True expressions:

  • The constants, -3 and -8, are like terms.  
  • The terms 3 p and p are like terms.  
  • The terms in the expression are p squared, negative 3, 3 p, negative 8, p, p cubed.
  • The expression contains six terms.
  • Like terms have the same variables raised to the same powers.

Step-by-step explanation:

The expression is:

p² - 3 + 3p - 8 + p + p³

False expressions:

  • The terms p squared, 3 p, p, and p cubed have variables, so they are like terms.  (They don't have the same exponents)
  • The terms p squared and p cubed are like terms.    (They don't have the same exponents)
  • The expression contains seven terms. (It contains 6 terms)
6 0
3 years ago
Read 2 more answers
Find the value of x then classify the triangle
Sliva [168]

Answer: 88º

Step-by-step explanation:

180-47=133-45=88

4 0
2 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
Help pleaseeeeeeeeeeeeee!!!!!!!!!!!!!!!! T^T
artcher [175]
1 + (-5/8) = 3/8

Explanation: If the coffee wasn’t drank it would’ve been at fraction 1 (or 100%)

Since he drank 5/8 of it. The coffee left is now 1-(5/8)

But since the question has asked to give the equation in addition format. Put a plus sign in between the two.

Therefore,
1 + (-5/8)

Solve it,
= 1-(5/8)
= (8-5)/8
= 3/8

Hence the equation is:

1 + (-5/8) = 3/8.
8 0
3 years ago
Read 2 more answers
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