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stepladder [879]
3 years ago
14

Help with thissssssss

Mathematics
2 answers:
kompoz [17]3 years ago
3 0

Answer:

27

Step-by-step explanation:

1^3 = 1

2^3 = 8

3^3 = 27

4^3 = 64

5^3 = 125

The missing number is 27.

spin [16.1K]3 years ago
3 0

Answer:

I think its 32 it have the most logic

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The area of a circle is 113.04 in.^2. What is the radius of the circle?
Lelechka [254]
\bf \textit{area of a circle}\\\\
A=\pi r^2\qquad 
\begin{cases}
r=radius\\
------\\
A=113.04
\end{cases}\implies 113.04=\pi r^2
\\\\\\
\cfrac{113.04}{\pi }=r^2\implies \sqrt{\cfrac{113.04}{\pi }}=r
5 0
3 years ago
What is the determinant of m= {5 8 -5 4} ? 20 40 60 80
likoan [24]

Answer:

60

Step-by-step explanation:

We have been given the matrix;

\left[\begin{array}{ccc}5&8\\-5&4\end{array}\right]

For a 2-by-2 matrix, the determinant is calculated as;

( product of elements in the leading diagonal) - (product of elements in the other diagonal)

determinant = ( 5*4) - (8*-5)

                     = 20 - (-40) = 60

3 0
3 years ago
Which point is on the graph of f(x) = 2*5^x
vodomira [7]

Answer:

Option B (1,10)

Step-by-step explanation:

we have

f(x)=2(5^x)

we know that

If a ordered pair is on the graph of f(x) then the ordered pair must satisfy the function f(x)

<u><em>Verify each case</em></u>

case A) (0,0)

For x=0

f(x)=2(5^0)\\f(x)=2(1)=2

Compare the value of f(x) with the y-coordinate of the ordered pair

2\neq 0

therefore

The ordered pair is not on the graph of f(x)

case B) (1,10)

For x=1

f(x)=2(5^1)\\f(x)=2(5)=10    

Compare the value of f(x) with the y-coordinate of the ordered pair

10=10

therefore

The ordered pair is on the graph of f(x)

case C) (0,10)

For x=0

f(x)=2(5^0)\\f(x)=2(1)=2

Compare the value of f(x) with the y-coordinate of the ordered pair

2\neq 10

therefore

The ordered pair is not on the graph of f(x)

case D) (10,1)

For x=10

f(x)=2(5^{10})\\f(x)=2(9,765,625)=19,531,250

Compare the value of f(x) with the y-coordinate of the ordered pair

19,531,250\neq 1

therefore

The ordered pair is not on the graph of f(x)

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