The cost of parking is an initial cost plus an hourly cost.
The first hour costs $7.
You need a function for the cost of more than 1 hour,
meaning 2, 3, 4, etc. hours.
Each hour after the first hour costs $5.
1 hour: $7
2 hours: $7 + $5 = 7 + 5 * 1 = 12
3 hours: $7 + $5 + $5 = 7 + 5 * 2 = 17
4 hours: $7 + $5 + $5 + $5 = 7 + 5 * 3 = 22
Notice the pattern above in the middle column.
The number of $5 charges you add is one less than the number of hours.
For 2 hours, you only add one $5 charge.
For 3 hours, you add two $5 charges.
Since the number of hours is x, according to the problem, 1 hour less than the number of hours is x - 1.
The fixed charge is the $7 for the first hour.
Each additional hour is $5, so you multiply 1 less than the number of hours,
x - 1, by 5 and add to 7.
C(x) = 7 + 5(x - 1)
This can be left as it is, or it can be simplified as
C(x) = 7 + 5x - 5
C(x) = 5x + 2
Answer: C(x) = 5x + 2
Check:
For 2 hours: C(2) = 5(2) + 2 = 10 + 2 = 12
For 3 hours: C(3) = 5(3) + 2 = 15 + 2 = 17
For 4 hours: C(3) = 5(4) + 2 = 20 + 2 = 22
Notice that the totals for 2, 3, 4 hours here
are the same as the right column in the table above.
X=percentage in decimal
30x=6
30/30x=6/30
x=1/5=.20
.20=20/100=20%
20%
I can’t see the question b
Answer:
The original duration of the tour is 18 days.
Step-by-step explanation:
Let
the number of days spent be T
Daily expenses be D
Initially ,
total tour expenses was 360
-------------(1)
If he extends his tour for 4 days, he has to cut down his daily expenses by dollar 3
---------------(2)
Expanding the eqaution(2)
DT-3D + 4T -12 = 360
Substituting the value of D
Solving the quadratic equation we get
T = 18 and T = -15
T is the number of gays and it cannot be negative , hence T is 18
Substituting in equation (1) we get
D = 20
