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alexdok [17]
2 years ago
5

A grain of sand has a diameter that is 2 mm long. Under a magnifying glass, it looks 20 mm long. What magnification was used?​

Mathematics
1 answer:
nikklg [1K]2 years ago
4 0

Answer:

Times 10 magnify

Step-by-step explanation:

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7. The points P(2, -3), Q(3, -2) and R(8, z) are
Hatshy [7]

Answer:

z = 3

Step-by-step explanation:

Since the points are collinear then the slopes between the points are equal.

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = P (2, - 3) and (x₂, y₂ ) = Q (3, - 2)

m = \frac{-2+3}{3-2} = 1

Repeat with

(x₁, y₁ ) = Q (3, - 2) and (x₂, y₂ ) = R (8, z )

m = \frac{z+2}{8-3} = \frac{z+2}{5} , then

\frac{z+2}{5} = 1 ( multiply both sides by 5 )

z + 2 = 5 ( subtract 2 from both sides )

z = 3

4 0
3 years ago
At a local river there were 48 alligators laying on the riverbank. if 5/6of the alligators were sleeping how many were awake
qaws [65]
8 alligator because is u divide 48/5 you get 40 and the remaining that r awake is 8
7 0
3 years ago
Can someone help me with this question please ​
postnew [5]

Answer:

which ones do you need??

7 0
3 years ago
Given the parent function f(x)=x^3 give the best description of the graph of y = -(2x)^3
GalinKa [24]

Answer:

Reflect and compress

Step-by-step explanation:

7 0
3 years ago
Please answer I’ll rate brainlyest
12345 [234]

Answer:

5P3*6C4=60*15=900

Step-by-step explanation:

5P3 refers to the permutations of 5 items taken 3 at a time. To evaluate this, we use factorials as follows;

5P3=\frac{5!}{(5-3)!}

The factorial of an integer n is evaluated as;

n!=n*(n-1)*(n-2)*(n-3).......3*2*1

Using this concept, the above expression can now be simplified as follows;

5P3=\frac{5!}{2!}=\frac{5*4*3*2!}{2!}=5*4*3=60

Therefore, the permutations of 5 items taken 3 at a time is 60.

The next expression, 6C4 refers to the combinations of 6 items taken 4 at a time. The simplification utilizes similar concepts of permutations since we shall be involving factorials;

6C4=\frac{6!}{4!(6-4)!}=\frac{6!}{4!*2!}=\frac{6*5*4!}{4!*2*1}=\frac{6*5}{2*1}=15

Therefore, the combinations of 6 items taken 4 at a time is 15.

The final step is to evaluate the product;

5P3*6C4=60*15=900

3 0
3 years ago
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