The function of f(4) = g(x+1) gives the value of x that is -1/5.
<h3>What is the function addition?</h3>
It is the addition of two functions similar to the addition of any two polynomial functions.
Given;
F(x)=x+1
g(x)=5x+1
We need to find f(4)=g(x+1)
First substitute x = 4 in f(x)
F(x)=x+1
F(4) = 4 + 1
F(4) = 5
Now substitute x = x + 1 in g(x)
g(x)=5x+1
g(x + 1) = 5(x + 1) + 1
g(x + 1) = 5(x + 1) + 1
g(x + 1) = 5x + 5 + 1
g(x + 1) = 5x + 6
Then ,
F(4) = g(x + 1)
5 = 5x + 6
5x = 5 - 6
5x = -1
x = -1/5.
The function of f(4) = g(x+1) gives the value of x that is -1/5.
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The answer for the first blank would be 1/2 because it had been dilated down to half it's original size. I hope this helps!
Answer: B. 4
Step-by-step explanation:
First, I did the equation out.
Second, I simply it all the way through.
Third, to get 4
3/2 and 9/10. Look at the denominators. 2 times what number equals 10. That number would be 5. So if you multiply the first fractions denominator by 5 you get 10. Do the same to the top. you get a new fracrion which is 15/10. Add normally. 15/10 + 9/10 = 24/10. In lowest terms it is 2 2/5 (2 wholes and 2 out of 5)
The answer is A; a=50t cause if you were to put 0, you would get 0 which is the first point, if you put in 1 you get 50, if you put in 2 you get 100 and so on.
