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Contact [7]
2 years ago
5

Lines j and k are intersected by line m. At the intersection of lines j and m, the uppercase left angle is 93 degrees. At the in

tersection of lines k and m, the bottom right angle is 93 degrees.
Given the information in the diagram, which theorem best justifies why lines j and k must be parallel?

alternate interior angles theorem
alternate exterior angles theorem
converse alternate interior angles theorem
converse alternate exterior angles theorem
Mathematics
1 answer:
alexandr402 [8]2 years ago
8 0

Answer: converse alternate exterior angles theorem

Step-by-step explanation:

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A library is open til' 5:00 P.M. On Wednesdays, the library closes 2 hours early. How many hours for a month is the library open
svet-max [94.6K]
So
if you assume that the month has 30 days and that the library opens at midnight, then
24 hours in a day
5 pm=12+5=17 hours
on wednessday=17-2=15 hours
wednessday=1/7 of week
so we find 1/7 of 30 which is 30/7=4 and 2/7
then subtract that from 30
30-4 and 2/7=25 and 5/7

ok so then we have
25 and 5/7 days is 17 hours and
4 and 2/7 days is 15 hours
so just multipy them and add

25 and 5/7 times 17=437.143 hours
4 and 2/7 days times 15 =64.2857
add

437.143+64.2856=501.429
so aprox 501.429

the real equation is  [(\frac{1}{7})(n)(15)]+[ (\frac{6}{7}) (n)(17)]=hours where n represents the number of days in the month

apros 501.429
8 0
3 years ago
Here's a graph of a linear function. Write the equation that describes that function.
Nataly [62]
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7 0
3 years ago
The sum of two consecutive integers is 37. Write an equation that models this situation and find the values of the two integers.
gizmo_the_mogwai [7]
n+n+1=37\\
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\boxed{n=18}\\
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5 0
3 years ago
Read 2 more answers
Determine the equation of the line with slope 3 that passes through the point (2, 0).
Hitman42 [59]

Answer:

m=2y-3

Step-by-step explanation:

8 0
3 years ago
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In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
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Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
3 years ago
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