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Andrew [12]
3 years ago
10

During the World Series the host city wide hotel occupancy rose 21% over the prior busiest night. If the busiest night had been

76% occupany, what was the new record? (use % symbol in answer)
Mathematics
2 answers:
nevsk [136]3 years ago
5 0
The busiest night had occupancy of 76%

During the World Series, the occupancy increased by 21% to a new record.
The new record is
76% + (76%)*0.21 = 76%*1.21 = 91.96%

Answer: 91.96%
malfutka [58]3 years ago
5 0

Answer:

91.96%.

Step-by-step explanation:

We have been given that during the World Series the host city wide hotel occupancy rose 21% over the prior busiest night. The busiest night had been 76% occupancy.

\text{New record}=\text{Old record+ Increase in old record}

To find the new record of occupancy, we will find 21% of 76% and add it to 76%.

\text{The new record}=76\%+({21\%\text{ of } 76\%)

\text{The new record}=\frac{76}{100}+({\frac{21}{100}\times\frac{76}{100})

\text{The new record}=0.76+({0.21\times 0.76)

\text{The new record}=0.76+0.1596

\text{The new record}=0.9196

Now let us convert our answer in percentage by multiplying our answer by 100.

\text{The new record}=0.9196\times 100=91.96\%

Therefore, the new record of occupancy was 91.96%.

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