Question

During the World Series the host city wide hotel occupancy rose 21% over the prior busiest night. If the busiest night had been 76% occupany, what was the new record? (use % symbol in answer)

Answer 1

The busiest night had occupancy of 76%

During the World Series, the occupancy increased by 21% to a new record.
The new record is
76% + (76%)*0.21 = 76%*1.21 = 91.96%

Answer: 91.96%

Answer 2

Answer:

91.96%.

Step-by-step explanation:

We have been given that during the World Series the host city wide hotel occupancy rose 21% over the prior busiest night. The busiest night had been 76% occupancy.

$\text{New record}=\text{Old record+ Increase in old record}$

To find the new record of occupancy, we will find 21% of 76% and add it to 76%.

$\text{The new record}=76\%+({21\%\text{ of } 76\%)$

$\text{The new record}=\frac{76}{100}+({\frac{21}{100}\times\frac{76}{100})$

$\text{The new record}=0.76+({0.21\times 0.76)$

$\text{The new record}=0.76+0.1596$

$\text{The new record}=0.9196$

Now let us convert our answer in percentage by multiplying our answer by 100.

$\text{The new record}=0.9196\times 100=91.96\%$

Therefore, the new record of occupancy was 91.96%.