Given:
The equation is:
To find:
The number that belongs in the green box and another box.
Solution:
We have,
Subtracting 2x from both sides, we get
Adding 2 on both sides, we get
We need to divide both sides by 3 to isolate the variable x.
On dividing both side by 3, we get
Therefore, the missing values are 3 and 3, and the required equation is .
F(g) = 4g+6
1. when g = 2, output f(2) = 14
answer: 14
2. output = 18
18 = 4g+6
4g = 12
g = 3
answer: 3
3.when g = 4
f(4) = 16+6=22
answer
(4,22)
4. when input = 6 means g=6
f(6) = 24+6 = 30
different = 30-6 = 24
answer: 24
Answer:
$20 Monday, 1/4 Thursday
Step-by-step explanation:
for Monday it said it cost 100$ and then you got 40% off and another 40% so 40 plus 40 is 80 and you still have 20$ left to pay
For Thursday it said 3/4 was eaten so there is only 1/4 is left
Yep!
Weighing #1: Start off by splitting the pile of 12 coins evenly into two piles, 6 in each pile. Put one pile on each side of the balance. The side that is weighed down has the fake coin it in. Ignore the other 6 coins.
Weighing #2: Now you have 6 coins left. Split the pile evenly again, 3 in each pile. Repeat the same process and put each pile on one side of the balance. The side that is weighed down has your fake coin in it. Ignore the other 3 coins.
Weighing #3: You have 3 coins left. Take two coins, whichever two you like, and weigh them. If they weigh the same, then the one you didn't weigh is the fake one. If one is heavier, then that heavier one is your fake coin.
You would multiply 44 by 11.
44×11=484
t=484
