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2 years ago

First five terms of n2+5

Mathematics

2 answers:

artcher [175]2 years ago

8 0

$a_n=n^2+5\\\\a_1=1^2+5=1+5=6\\\\a_2=2^2+5=4+5=9\\\\a_3=3^2+5=9+5=14\\\\a_4=4^2+5=16+5=21\\\\a_5=5^2+5=25+5=30$

Travka [436]2 years ago

8 0

N=1 --- 1(2)+5 --- 2+5 --- 7
n=2 --- 2(2)+5 --- 4+5 --- 9
n=3 --- 3(2)+5 --- 6+5 --- 11
n=4 --- 4(2)+5 --- 8+5 --- 13
n=5 --- 5(2)+5 --- 10+5 --- 15

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Which linear equation would produce a y-intercept of (0, 5) and a slope of 7?

Dafna11 [192]

Answer:

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Step-by-step explanation:

sub into y= mx + c

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1 year ago

In 2017 the population of Rexburg, Idaho was 28,337 people. The population was expected to grow at a rate of about 1.26% per yea

frez [133]

Answer:

30,122

Step-by-step explanation:

This probably isn't the fastest way to solve but....

28,337x1.26%= 357

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2 years ago

Fred walked a trail at 2 mph. Paul started 30 minutes later on the same trail and walked at a pace of 3 mph. Create a system of

spayn [35]

Answer:

$y=2x\\y=3(x-\frac{1}{2})$

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Step-by-step explanation:

Distance is represented by $y$ and the time is represented by $x$ . Here after $x$ hours(when Fred started) the distance covered by Fred and Paul is same that is $y$ .

For Fred:

time= $x$

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Speed $=2\ mph$

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Since Fred started 30 minutes earlier, so Paul's travel time will be 30 minutes less than that of Fred.

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Distance $=y\\$

$y=3\times (x-\frac{1}{2})\\y=3(x-\frac{1}{2})$

Hence system of equation

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Solution of this system of equations gives the time, when Paul will catch Fred and distance covered by each of them.

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Hence Paul will catch Fred after $1\ hours$ at a distance $3\ miles$ .

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2 years ago

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ASHA 777 [7]

Answer:

So using the same formula that we came from the last question

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We find for C by making C the subject of the formula

$3.65c = 803 - 335.80$

$c = (803 - 335.80) \div 3.65$

We now evaluate

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3 years ago

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almond37 [142]

14^a is your answer hope i helped you
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3 years ago