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lord [1]
3 years ago
5

First five terms of n2+5

Mathematics
2 answers:
artcher [175]3 years ago
8 0
a_n=n^2+5\\\\a_1=1^2+5=1+5=6\\\\a_2=2^2+5=4+5=9\\\\a_3=3^2+5=9+5=14\\\\a_4=4^2+5=16+5=21\\\\a_5=5^2+5=25+5=30
Travka [436]3 years ago
8 0
N=1 --- 1(2)+5 --- 2+5 --- 7
n=2 --- 2(2)+5 --- 4+5 --- 9
n=3 --- 3(2)+5 --- 6+5 --- 11
n=4 --- 4(2)+5 --- 8+5 --- 13
n=5 --- 5(2)+5 --- 10+5 --- 15
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DochEvi [55]

Answer:

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant   2 • 2 = 4  

Step-2 : Find two factors of  4  whose sum equals the coefficient of the middle term, which is   3 .

     -4    +    -1    =    -5  

     -2    +    -2    =    -4  

     -1    +    -4    =    -5  

     1    +    4    =    5  

     2    +    2    =    4  

     4    +    1    =    5  

Observation : No two such factors can be found !!

4 0
3 years ago
Can anyone help me this was literally due over a week ago
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Step-by-step explanation:

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3 years ago
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