The applicable decay formula is:N = No*e^(-kt)WhereN = Mass left after time tNo = Original massk = constantt = half lifeUsing the values given,N/No = e^(-0.1446t) = 1/2ln (1/2) = -0.1446 t *ln e^1-0.6931 = -0.1446 tt = 0.6331/0.1446 = 4.79 daysTherefore, half-life is 4.8 days.
The answer is 0.333, or 1/3
29.7 IBS and you would get it by doing 178.2/ 6
Answer:
3 units to the right 5 units up
Step-by-step explanation:
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Answer:
Step-by-step explanation:
4-8 = -4
Thus, the answer is - 4/3
