from the diagram, we can see that the height or line perpendicular to the parallel sides is 8.5.
likewise we can see that the parallel sides or "bases" are 24.3 and 9.7, so
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=8.5\\ a=24.3\\ b=9.7 \end{cases}\implies \begin{array}{llll} A=\cfrac{8.5(24.3+9.7)}{2}\\\\ A=\cfrac{8.5(34)}{2}\implies A=144.5~in^2 \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D8.5%5C%5C%20a%3D24.3%5C%5C%20b%3D9.7%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B8.5%2824.3%2B9.7%29%7D%7B2%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B8.5%2834%29%7D%7B2%7D%5Cimplies%20A%3D144.5~in%5E2%20%5Cend%7Barray%7D)
Answer:
5+4+7
Step-by-step explanation:
I think
This differs on what number you want to talk about. 1 is the hundreds, 8 is the tenths, 7 is the ones.
<span>(a) At the end of Month 0, about how many more insects were in Pod A than Pod B? Explain.
In Pod A, the point is higher than 50, it could be 60 to 70 insects. Pod B has 20 insects. So, Pod A has at least 40 insects more than Pod B.
(b) Find and compare the growth rates of each pod. Show your work.
Pod A: (0,60) ; (1,80) ; (2,100)
(80-60)/60 = 0.33
(100-80)/80 = 0.25
Pod B: (0,20) ; (1,44) ; (2,97)
(44-20)/20 = 1.2
(97-44)/44 = 1.2
Based on my computation, the rate of Pod A is lower than the rate of Pod B.
(c) When does the population in Pod B exceed the population in Pod A? Explain.
Pob B exceeds the population of Pod A at the END OF MONTH 4.
Pod A has a population of less than 200 while Pod B has a population of 469.</span>
