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Anon25 [30]
3 years ago
14

What is the error? 1.5x-2=-2+1.5x -2=2

Mathematics
2 answers:
OLga [1]3 years ago
7 0
They removed the variable from both sides of the equation instead of just from one side!
Kryger [21]3 years ago
5 0

Answer:

obj?

Step-by-step explanation:

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Taylor can solve riddles very quickly. She solved 11 riddles in 4 minutes. How many did she solve each minute?​
KengaRu [80]

Answer:

2 riddles every minute!

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Write an equation for the line that is parallel to the given line and passes through the given point Y= 1/2 x -8 (-6 ,-17)
mylen [45]
Parallel to : y = 1/2x - 8

Passes through (-6, -17)

Our given slope is 1/2.

Plug the given coordinates into point-slope form.

y - y₁ = m(x - x₁)

y - (-17) = 1/2(x - (-6))

Simplify.

y + 17 = 1/2(x + 6)  ← Your answer.

However, sometimes teachers want this simplified even further.

So, simplify this.

y + 17 = 1/2x + 3

Subtract 17 from both sides.

y = 1/2x + 3 - 17

Simplify.

y = 1/2x - 14 ← Slope-intercept form.

Standard form → -1/2x + y = -14


~Hope this helped!~
8 0
3 years ago
Please answer this quickly! Find the next two numbers in the pattern. 1875, -375,75,?,?
agasfer [191]
Hope this helps sorry if it’s wrong
7 0
2 years ago
Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21

Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5
6 0
3 years ago
Can someone please tell me what the formula to find area and volume for this would be?
Step2247 [10]
The formula for this is A= a + b/2 x h.
6 0
3 years ago
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