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Anon25 [30]
3 years ago
14

What is the error? 1.5x-2=-2+1.5x -2=2

Mathematics
2 answers:
OLga [1]3 years ago
7 0
They removed the variable from both sides of the equation instead of just from one side!
Kryger [21]3 years ago
5 0

Answer:

obj?

Step-by-step explanation:

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Sum the following numbers then divide by 5
Brilliant_brown [7]

Answer:

4

Step-by-step explanation:

(3+5+6+2+4) / 5 = ?

(20) / 5 = 4

4 0
4 years ago
What is the equation of this line?<br><br><br>y = 2x<br><br>y=12x<br><br>y=−2x<br><br>y=−12x
Anna [14]
Y=2X

Looking at the line you can see that it is moving up from left to right, making it positive. So -2X and -12X are incorrect.

Next we can find the slope by putting rise over run. Chose a point on the line, I’ll use (2,4).
On this point we rise to 4 and run over to 2.
So for rise over run we have 4/2 which is 2.
So y=2x is correct.
6 0
3 years ago
Suppose there are 175 tickets available for a school play.
klio [65]

Answer: 77 tickets

Step-by-step explanation: 175 - 98 = 77

8 0
3 years ago
Plz help me with number 8 plz help me I’m begging you plz help me I need your help plz help me I’m begging you plz help me
vampirchik [111]

Answer:

B. 990<s<1,850

6 0
3 years ago
Read 2 more answers
How much charge is needed to repel another charge of 9.9 x 10^-6 N when they are 200m apart? Please help meee I really can't und
fenix001 [56]

Answer:

The charge needed will be q=6.6\: \mu C

Step-by-step explanation:

The equation of the electric force is given by:

F=k\frac{qQ}{r^{2}}

We have the force F = 9.9 10^{-6}\: N  and the distance r = 200. k is the Coulomb constant. Q and q are the charges.

We assume we have the same charge of the particles,  so we have:

q^{2}=\frac{Fr^{2}}{k}

q^{2}=\frac{9.9*10^{-6}200^{2}}{9*10^{9}}

q=6.6*10^{-6}\: C

Therefore, the charge needed will be q=6.6\: \mu C

I hope it helps you!

8 0
3 years ago
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