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3 years ago

1) y=-3x + 4 y = 3x - 2 (1,1)

Mathematics

1 answer:

puteri [66]3 years ago

7 0

Answer:

y=3x-2

Step-by-step explanation:

your question didn't have any instructions so this might not be what you're looking for

set them equal to each other

-3x+4=3x-2

-3x-3x=-2-4

-6x=-6

x=1

plug in x=1

y=3(1)+4 =7

y=3(1)-2 =1

so, when x=1, y=1 in the expression y=3x-2

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The 11th term in a geometric sequence is 48.

The 12th term in the sequence is 192.

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We need to determine the 10th term of the sequence.

General term:

The general term of the geometric sequence is given by

$a_n=a(r)^{n-1}$

where a is the first term and r is the common ratio.

The 11th term is given is

$a_{11}=a(4)^{11-1}$

$48=a(4)^{10}$ ------- (1)

The 12th term is given by

$192=a(4)^{11}$ ------- (2)

Value of a:

The value of a can be determined by solving any one of the two equations.

Hence, let us solve the equation (1) to determine the value of a.

Thus, we have;

$48=a(1048576)$

Dividing both sides by 1048576, we get;

$\frac{3}{65536}=a$

Thus, the value of a is $\frac{3}{65536}$

Value of the 10th term:

The 10th term of the sequence can be determined by substituting the values a and the common ratio r in the general term $a_n=a(r)^{n-1}$ , we get;

$a_{10}=\frac{3}{65536}(4)^{10-1}$

$a_{10}=\frac{3}{65536}(4)^{9}$

$a_{10}=\frac{3}{65536}(262144)$

$a_{10}=\frac{786432}{65536}$

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1) y=-3x + 4 y = 3x - 2 (1,1)​

1) y=-3x + 4 y = 3x - 2 (1,1)