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2 years ago

I'd also appreciate if someone would help me out with this, thank you

Mathematics

2 answers:

S_A_V [24]2 years ago

4 0

Answer:

c=42

Step-by-step explanation:

First you would find out how much you would add to 45 to give you 66. Which is 21. Then you double it, so when you put it over the two it looks like this 42/2. So when you reduce the fraction you get 21. Hence 21+45=66.

Hope this helps!

sladkih [1.3K]2 years ago

3 0

Answer:

C = 42

Step-by-step explanation:

½ c + 45 = 66

½ c + 45 − 45 = 66 − 45

2 × (½ c) = 2 × 21

C = 42

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Imagine you are a financial analyst at an investment bank. According to your research of publicly-traded companies, 60% of the c

lilavasa [31]

Answer:

0.0667 = 6.67% probability that the shares of a company that fires its CEO will increase by more than 5%.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem:

Event A: Company fires the CEO

Event B: Shares increase by more than 5%.

Probability of a company firing it's CEO:

35% of 100 - 4 = 96%(shares did not increase by more than 5%).

60% of 4%(shared did increase by more than 5%).

$P(A) = 0.35*0.96 + 0.6*0.04 = 0.36$

Intersection of events A and B:

Fires the CEO and shared increased by more than 5%, is 60% of 4%. So

$P(A \cap B) = 0.6*0.04 = 0.024$

Probability that the shares of a company that fires its CEO will increase by more than 5%.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.024}{0.36} = 0.0667$

0.0667 = 6.67% probability that the shares of a company that fires its CEO will increase by more than 5%.

5 0

3 years ago

To solve the inequality m/-7<(or equal to) 14 , what should be done to both sides?

Marizza181 [45]

Answer:

$\large\boxed{m\geq-98}$

Step-by-step explanation:

$\dfrac{m}{-7}\leq14\\\\-\dfrac{m}{7}\leq14\qquad\text{change the signs}\\\\\dfrac{m}{7}\geq-14\qquad\text{multiply both sides by 7}\\\\7\!\!\!\!\diagup^1\cdot\dfrac{m}{7\!\!\!\!\diagup_1}\geq(7)(-14)\\\\m\geq-98$