Answer:
The substance that remained on the filter paper is Al(OH).
Explanation:
- Filter paper is the substance that is used in laboratory to separate the solid objects. It doesn't filter aqueous and gaseous products.
- So in our experiment the product formed is aluminum hydroxide Al(OH) and sodium chloride (NaCl).
- Between two products, sodium chloride is in aqueous form as indicated in the question. So it wont remain in the filter paper.
- Hence aluminum hydroxide being only solid product remains on the filter paper.
Answer:
Standard reduction potential is an intensive property---- True
Reduction takes place at the anode ----- False
The half reaction with the lower standard reduction potential will be at the cathode in a galvanic cell ------false
The half reaction with the higher standard reduction potential will be at the cathode in a galvanic cell ------ True
Explanation:
An intensive property is a property of a substance which is inherent in it and part of its nature. It does not depend on the amount of substance present in the substance. Standard reduction potential is an intensive property.
In a galvanic cell, oxidation takes place at the anode and reduction takes place at the cathode. At the anode, the electrode potential is more negative (an oxidation) while at the cathode the reduction potential is less negative (a reduction).
<h3><u>Answer;</u></h3>
= 9.45 × 10^23 molecules
<h3><u>Explanation; </u></h3>
The molar mass of Na2SO4 = 142.04 g/mol
Number of moles = mass/molar mass
= 223/142.04
= 1.57 moles
But;
1 mole = 6.02 × 10^23 molecules
Therefore;
1.57 moles = ?
= 1.57 × 6.02 × 10^23 molecules
<u>= 9.45 × 10^23 molecules </u>
