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PtichkaEL [24]
3 years ago
15

Determine if the following statements are true or false. True Standard reduction potential is an intensive property True Reducti

on takes place at the anode True The half reaction with the lower standard reduction potential will be at the cathode in a galvanic cell True The half reaction with the higher standard reduction potential will be at the cathode in a galvanic cell
Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

Standard reduction potential is an intensive property---- True

Reduction takes place at the anode ----- False

The half reaction with the lower standard reduction potential will be at the cathode in a galvanic cell ------false

The half reaction with the higher standard reduction potential will be at the cathode in a galvanic cell  ------  True

Explanation:

An intensive property is a property of a substance which is inherent in it and part of its nature. It does not depend on the amount of substance present in the substance. Standard reduction potential is an intensive property.

In a galvanic cell, oxidation takes place at the anode and reduction takes place at the cathode. At the anode, the electrode potential is more negative (an oxidation) while at the cathode the reduction potential is less negative (a reduction).

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Answer:

P (H₂) = 741 torr

Explanation:

Let's begin by listing out the given parameters:

Temperature (water) = 298 K, volume = 45.6 mL,

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To get the pressure of inside the tube, P (H₂), we apply Dalton's Law of Partial Pressure and we have:

P (total) = P (H₂) + P (H₂O)

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Entropy means the amount of randomness present within the molecules of the body of a substance.

Relation between entropy and microstate is as follows.

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             K_{b} = Boltzmann constant

             \Omega = number of microstates

This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.

Also, let us assume that \Omega = 1, and \Omega' = 0.833

Therefore, change in entropy will be calculated as follows.

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                 = 1.38 \times 10^{-23} \times (-0.182)

                 = -0.251 \times 10^{-23}

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Thus, we can conclude that the entropy change for a particle in the given system is -2.51 \times 10^{-24} J/K particle.

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Answer:

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