Answer:
The ratio 35Cl/37Cl = 3/1
Explanation:
<u>Step 1:</u> Data given
Chlorine has 2 isotopes:
- mass = 35 g/mol
- mass = 37 g/mol
Average molar mass of chlorine = 35.5 grams
<u>Step 2: </u>Calculate the % of isotopes
35x + 37y = 35.5
x+y = 1 or x = 1-y
35(1-y) + 37y = 35.5
35-35y +37y = 35.5
0.5 = 2y
y = 0.25 = 37Cl
x = 1 - 0.25 = 0.75 = 35Cl
<u>Step 3: </u>
The ratio 35Cl/37Cl = 0.75/0.25 = 3/1
<span>Ionization energy (IE) is the amount of energy required to remove an electron.
If you observe the IEs sequentially, there is a large gap between the 2nd and 3rd. This suggests it is difficult to remove more than 2 two electrons. Elements that lose two electrons to become more stable are found in the Group 2A (2 representing the number of electrons in the outermost valence shell).</span>
Answer: Heterogeneous Mixture
Explanation:
Answer:
Cardiac output (CO) = 8.54 l / min
Explanation:
Given:
Oxygen consumption (V) = 1.41 l O2/min
Oxygen in arterial (Ca) = 190 ml O2/L = 0.19 l O2/L
Oxygen in venous (Cv) = 25 ml O2/L = 0.025 l O2/L
Find:
Cardiac output (CO)
Computation:
Cardiac output (CO) = V / (Ca - Cv)
Cardiac output (CO) = 1.41 / (0.19 - 0.025)
Cardiac output (CO) = 8.54 l / min
