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Nookie1986 [14]
3 years ago
6

9. A student observed the following reaction:

Chemistry
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

The substance that remained on the filter paper is Al(OH).

Explanation:

  • Filter paper is the substance that is used in laboratory to separate the solid objects. It doesn't filter aqueous and gaseous products.
  • So in our experiment the product formed is aluminum hydroxide Al(OH)   and sodium chloride (NaCl).
  • Between two products, sodium chloride is in aqueous form as indicated in the question. So it wont remain in the filter paper.
  • Hence aluminum hydroxide being only solid product remains on the filter paper.
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The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha
zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

P (Half-life) = 10.0 minutes

T (Elapsed time for sample reduction) = 25.9 minutes

Let's find the number of periods elapsed (x), let us see:

T = x*P

25.9 = x*10.0

25.9 = 10.0\:x

10.0\:x = 25.9

x = \dfrac{25.9}{10.0}

\boxed{x = 2.59}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{53.3}{2^{2.59}}

m \approx \dfrac{53.3}{6.021}

\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

3 0
3 years ago
Why do scientist use models to study atoms and molecules?
Nesterboy [21]
This allows us to visually see the structure of the atoms/ molecules so we can get a better understanding of what they look like.
6 0
3 years ago
Due in minutes! Please Help Solve!
stiks02 [169]
Step by step equation
5 0
3 years ago
C. How many moles of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg?
olya-2409 [2.1K]

Answer: There are 4.45\times 10^{-4}moles of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 895 mm Hg= 1.18 atm  (760 mm Hg= 1 atm)

V = Volume of gas = 9.55 ml = 0.00955 L   (1 L=1000ml)

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =35^0C=(35+273)K=308K

n=\frac{PV}{RT}

n=\frac{1.18atm\times 0.00955L}{0.0821L atm/K mol\times 308K}=4.46\times 10^{-4}moles

Thus there are 4.45\times 10^{-4}moles of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg

5 0
3 years ago
A 20 ml sample of .875 m hcl solution was diluted t o150 ml. calculate the molarity of the resulting solution
Veronika [31]
0.11666667 because M1V1=M2V2
4 0
3 years ago
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