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Nimfa-mama [501]
2 years ago
8

Can someone help me I need this done ASAP like TODAY… I know D. I just dont know A, B, C. Please helppppppppp meeeeeeeeee

Mathematics
1 answer:
ivann1987 [24]2 years ago
6 0

Answer:

Please see explanation

Step-by-step explanation:

base= -3

the exponent is 5

in expanded form -3×-3×-3×-3×-3

evaluation = -3×-3×-3×-3×-3= -243

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-2(5p – 3) = 26<br> Explain your answer.<br> 30 points.
otez555 [7]
The answer would be p= -2

To check it:
-2(5(-2) - 3) = 26
-2(-10-3) = 26
-2(-13) = 26
26 = 26

4 0
3 years ago
How many flowers, spaced every 6 inches, are needed to surround a circular garden with a 10 foot radius?
Stolb23 [73]

To solve this problem you must apply the proccedure shown below:

1. You must calculate the perimeter of the circle:

The radius of the circle in inches is:

radius=\frac{(10ft)(12in)}{1ft}=120in

P=2\pi(radius)\\  P=2\pi(120in)\\ P=753.98in

2. Now, you must divide the perimeter by the space between each flower to find the number of flowers needed, which you can call x:

x=\frac{753.98in}{6in}=125.6=126

The answer is: 126 flowers.

5 0
3 years ago
Arun’s restaurant bill is $58, and he wants to leave the waiter an 18 percent tip. What will Arun’s total bill be?
Natalka [10]

Answer:

68.44

Step-by-step explanation:


6 0
4 years ago
Read 2 more answers
A pizza parlor offers pizzas with diameters of 8 in, 10 in, and 12 in. find the area of each size pizza. round to the nearest te
MaRussiya [10]
Area od pizza, A = Pi*Diameter^2/4

A1 = Pi*8^2/4 = 50.27 in^2
A2 = Pi*10^2/4 = 78.54 in^2
A3 = Pi*12^2/4 = 113.10 in^2

Cost (C) per sq. in;
C1 = 50.27/9 = $5.59
C2 = 78.54/12 = $6.55
C3 = 113.10/18 = $6.28

The best buy is the first pizza with 8 in diameter as it costs the least per sq. inch.
3 0
3 years ago
Read 2 more answers
Which is the solution to the equation solved for p? (q + p)q = (s + r)s
Brums [2.3K]

Answer:

Option B

Step-by-step explanation:

(q + p)q = (s + r)s

Lets open the brackets of L.H.S.

=> q^2 + pq = (s+ r)s

Lets substract q² from both the sides.

=> q^2 + pq - q^2 = (s + r)s - q^2

=> pq = (s + r)s - q^2

Lets divide both the sides by q.

=> \frac{pq}{q} = \frac{(s + r)s - q^2}{q}

=> p = \frac{(s + r)s }{q} - \frac{q^2}{q} = \frac{(s + r)s}{q} - q

7 0
3 years ago
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