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disa [49]
2 years ago
13

What is the molarity of a solution in which 250 grams of NaCl are dissolved in 2.9 L of water?

Chemistry
1 answer:
Maksim231197 [3]2 years ago
3 0

Answer:

About 1.48 M.

Explanation:

The formula for molarity is mol/L.

So firstly, you must find the amount of moles in 250 grams of NaCl.

I do this by using stoichiometry. First, I find how nany grams are in a single mole of NaCl. This is around 58.44 grams/mole. Now that I know this, I can now use a stoich table. (250 g NaCl * 1 mol NaCl / 58.44 g NaCl). I plug this into my calculator.

I get that 250 grams of NaCl is equal to about 4.28 moles.

Now I just plug into the formula!

4.28 moles/2.9 L = about 1.48

<em><u>I've</u></em><em><u> </u></em><em><u>attached</u></em><em><u> </u></em><em><u>a </u></em><em><u>picture </u></em><em><u>of </u></em><em><u>my </u></em><em><u>personal </u></em><em><u>notes </u></em><em><u>below </u></em><em><u>which </u></em><em><u>shows </u></em><em><u>work </u></em><em><u>I </u></em><em><u>have </u></em><em><u>done</u></em><em><u> </u></em><em><u>in </u></em><em><u>similar </u></em><em><u>equations.</u></em>

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