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topjm [15]
2 years ago
12

Why does benzilic acid only precipitate in acidic solution.

Chemistry
1 answer:
Maksim231197 [3]2 years ago
8 0

Benzilic acid will only precipitate in acidic solution to remove excess acid and restore equilibrium.

<h3 /><h3>What are is chemical equilibrium?</h3>

Chemical equilibrium refers to a state in which the rate at which reactant molecules combine to form products is equal to the rate at which products dissociate to form reactants.

For a reaction in equilibrium, any change to distort the equilibrium will cause equilibrium to shift to counter that change.

The components of Benzilic acid exist in equilibrium and will only precipitate in acidic solution because more acid has been added and equilibrium will shift to removal of excess acids.

Therefore, benzilic acid only precipitate in acidic solution in order to remove excess acid and restore equilibrium.

Learn more about chemical equilibrium at: brainly.com/question/19340344

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How many moles of oxygen atom are there in 0.5 moles of Ca(ClO3) 2?
FinnZ [79.3K]

Answer:

Do a quick conversion: 1 moles Ca(ClO3)2 = 206.9804 gram using the molecular weight calculator and the molar mass of Ca(ClO3)2. ... How many moles Ca(ClO3 )2 in 1 grams? ... of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.

Explanation:

(jayaanilanmol's answer)

3 0
4 years ago
A gas mixture with a total pressure of 750 mmHg contains each of the following gases at the indicated partial pressures: CO2 , 1
jolli1 [7]

Answer: a) 211 mm Hg

b) 0.629 grams

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_1+p_2+p_3+p_4

p_{total} = total pressure = 750 mmHg

p_{CO_2} = 124 mm Hg

p_{Ar} = 218 mm Hg

p_{O_2} = 197 mm Hg

p_{He} = ?

750 mmHg=124 mm Hg+218 mm Hg+197 mm Hg+p_{He}

p_{He}=211mmHg

Thus  the partial pressure of the helium gas is 211 mmHg.

b) According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = 211 mmHg = 0.28 atm   (760mmHg=1atm)

V= Volume of the gas = 13.0 L

T= Temperature of the gas =  282 K  

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= ?

n=\frac{PV}{RT}=\frac{0.28\times 13.0}0.0821\times 282}=0.157moles

Mass of helium= moles\times {\text {molar mass}}=0.157\times 4=0.629g

Thus mass of helium gas present in a 13.0-L sample of this mixture at 282 K is 0.629 grams

8 0
4 years ago
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Serjik [45]

Answer:

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Explanation:

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2 years ago
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3 years ago
Read 2 more answers
What is the pOH of 0.5 M KOH?
jenyasd209 [6]

Answer:

pOH = 0.3

Explanation:

As KOH is a strong base, the molar concentration of OH⁻ is equal to the molar concentration of the solution. That means that in this case:

  • [OH⁻] = 0.5 M

With that information in mind we can<u> calculate the pOH </u>by using the following formula:

  • pOH = -log[OH⁻]
  • pOH = -log(0.5)
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5 0
3 years ago
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