The length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.
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Length of the entire hydrogen atoms</h3>
The length of the entire hydrogen atom is calculated as follows;
Length of the row = number x diameter of one
Length of the row = 4.34 x 10²³ x 10⁶ x 10⁻¹²
Length of the row = 4.34 x 10¹⁷ m
Length of the row = 4.34 x 10¹⁴ km
Thus, the length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.
Learn more about diameter of hydrogen atom here: brainly.com/question/13796082
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Answer:
2Na=Ca(OH)000.1 AgBr=2KF 2KBr=LiNO
Answer: im thinking its gonna be d.C2H6 and also
the explanation is on the research i had did before i had answered this question so i really hope this help :)
Explanation:
Ar = van de waals forces or london forces
C
H
4
= van de waals forces or london forces
HCl=permanent dipole-dipole interactions
CO = permanent dipole-dipole interactions
HF = hydrogen bonding
N
a
N
O
3
= permanent dipole-dipole interactions
C
a
C
l
2
= van de waals forces or london forces
