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seropon [69]
3 years ago
9

What is the pOH of 0.5 M KOH?

Chemistry
1 answer:
jenyasd209 [6]3 years ago
5 0

Answer:

pOH = 0.3

Explanation:

As KOH is a strong base, the molar concentration of OH⁻ is equal to the molar concentration of the solution. That means that in this case:

  • [OH⁻] = 0.5 M

With that information in mind we can<u> calculate the pOH </u>by using the following formula:

  • pOH = -log[OH⁻]
  • pOH = -log(0.5)
  • pOH = 0.3
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Charles’ Law can be expressed mathematically as V=kT. If the constant k for 6.0 L of gas is 0.020 L/K (liters per kelvin), what
kozerog [31]

Answer: 300 K

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T    (At constant pressure and number of moles)

V=kT

Given : V= 6.0 L

k= 0.020 L/K

T=?

6.0=0.020LK^{-1}\times T

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3 0
3 years ago
Find the formula for the hydrate<br>0.737 g MgSO3 and 0.763 g H2O
babunello [35]

The required formula of hydrate is MgSO₃.6H₂O.

<h3>How do we calculate the formula of hydrate?</h3>

The number of moles of water per mole of anhydrous solid (x) will be computed by dividing the number of moles of water by the number of moles of anhydrous solid (x) to find the hydrate's formula.

Moles will be calculated as:
n = W/M, where

  • W = given mass
  • M = molar mass

Moles of MgSO₃ = 0.737g / 104.3g/mol = 0.007mol

Moles of H₂O = 0.763g / 18g/mol = 0.04 mol

Number of H₂O molecule = 0.04/0.007 = 5.7 = 6

So formula of hydrate is MgSO₃.6H₂O.

Hence required formula of hydrate compound is MgSO₃.6H₂O.

To know more about hydrate compound, visit the below link:

brainly.com/question/22411417

#SPJ1

6 0
2 years ago
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