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Dima020 [189]
1 year ago
7

Please show your work, tysm :D ~giving brainliest!~

Mathematics
1 answer:
N76 [4]1 year ago
5 0

Answer:

. 0625

Step-by-step explanation:

1/2^4

or

1/16

just doing half life

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What are three ways a rectangle and a square are alike
k0ka [10]

-- Each has 4 sides.
-- Opposite sides of each are parallel.
-- Opposite sides of each have equal length.
-- Interior angles of each sum to 360 degrees.
-- Each is a special case of parallelogram.
-- Each has all interior angles equal.
-- Area of either one is (length) x (width).


3 0
3 years ago
Read 2 more answers
What are the vertex focus and directrix of a parabola with equation x=y^2+14y-2
zimovet [89]
This is a sideways opening parabola, opening to the right to be more specific, since the leading coefficient is a positive 1.  The rule for a focus and a directrix is that they are the same number of units from the vertex (in other words, the vertex is dead center between them), and that the vertex is on the same axis that the focus is.  We need to find the vertex then to determine what the focus and the directrix are.  We will complete the square on that to find the vertex.  Begin by setting it equal to 0, then move the 2 over by addition to get y^2+14y=2.  Now we will complete the square on the y terms.  Take half the linear term, square it, and add it to both sides.  Our linear term is 14.  Half of 14 is 7, and 7 squared is 49. So we add 49 to both sides. y^2+14y+49=2+49, which of course simplifies to y^2+14y+49=51.  The purpose of this is to find the k coodinate of the vertex which will be revealed when we write the perfect square binomial we created during this process: (y+7)^2=51.  Moving the 51 back over by subtraction gives us (y+7)^2-51=x.  The vertex then is (-51,-7).  The formula to find the focus using this vertex is (h+ \frac{1}{4a},k).  As I stated quite a while ago, the leading coefficient on our parabola was a +1 so our "a" value is 1, and the focus is then found in (-51+ \frac{1}{4},-7) which simplifies to (-50.75, -7).  If the vertex is (-51, -7) and the focus is (-50.75, -7), then the distance between them is 1/4, or .25.  That means that the directrix is also .25 units from the vertex, but in the other direction.  Our directrix is a vertical line, and it will have the equaion x = -51.25.  Summing up, your focus is (-50.75, -7) and your directrix is x = -51.25
7 0
3 years ago
The angles of a quadrilateral measure 80, 100, 100, 80 in this order what kind of quadrilateral has this shape what attributes h
Harrizon [31]

Answer:

Isosceles trapezoid

Step-by-step explanation:

-An isosceles trapezoid is also sometimes called a convex quadrilateral.

-It properties include:

  • A line of symmetry can often bisects a pair of opposite sides.
  • It has to obtuse alternating with each other after which a pair of acute angles alternate with each other i.e 80°, 80°,100°,100°
  • It has a trapezoidal shape which by definition has a two pair of parallel sides.
  • The angles on it's base or ceiling are equal hence the name Isosceles Trapezoid.

8 0
3 years ago
What’s an equation that passes through the ordered pair (3,7)and has a slope of -4
natita [175]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

y = mx + b

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

According to the statement data we have:

m = -4\\(x, y) :( 3,7)

Then, the equation is of the form:

y = -4x + b

We substitute the given point and find "b":

7 = -4 (3) + b\\7 = -12 + b\\7 + 12 = b\\b = 19

Finally, the equation is of the form:

y = -4x + 19

Answer:

y = -4x + 19

6 0
2 years ago
Given s(x) = 2x - 3 and t(x) = 5x + 4. find the formula and domain for s(x) over t(x) and w(x) = t(x) over s(x)
attashe74 [19]
V(x) = (2x - 3)/(5x + 4)   The domain is all Real numbers except x = -4/5, because if x = -4/5 the denominator would be zero and you cannot divide by zero.{x | x ∈ R, x ≠ -4/5} w(x) = (5x + 4)/(2x - 3)similarly, x ≠ 3/2so, {x| x ∈ R, x ≠ 3/2}
6 0
3 years ago
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