Total distance the rover need to travel is
.
<u>Step-by-step explanation:</u>
We have , Garne Problem med . A rover needs to travel mile to reach its destination traveled mile. a rover needs to travel 5/8 mile to reach its destination it has already travel 3/8 miles . We need to find that how much farther does the rover need to travel , Let's do it step by step:
First , rover has already traveled 3/8 miles , Let total distance to be traveled by rover is D :
⇒
, where d is distance left to cover .
Now, rover need to travel 5/8 miles more to reach destination :
⇒
, where d is distance left to cover , So
⇒
⇒ ![D = \frac{3}{8} + \frac{5}{8}](https://tex.z-dn.net/?f=D%20%3D%20%5Cfrac%7B3%7D%7B8%7D%20%2B%20%5Cfrac%7B5%7D%7B8%7D)
⇒ ![D = \frac{3+5}{8}](https://tex.z-dn.net/?f=D%20%3D%20%5Cfrac%7B3%2B5%7D%7B8%7D)
⇒ ![D = \frac{8}{8}](https://tex.z-dn.net/?f=D%20%3D%20%5Cfrac%7B8%7D%7B8%7D)
⇒ ![D = 1miles](https://tex.z-dn.net/?f=D%20%3D%201miles)
∴ Total distance the rover need to travel is
.
Answer:
this is a confusing one
Step-by-step explanation:
Answer: Laundry = $2
Dishes= $1
Step-by-step explanation:
Let the amount paid for doing laundry be x
Let the amount paid for doing dishes be y.
Based on the information in the question, this can be formed in an equation as:
5x + 8y = 18 ..... i
4x + 6y = 14 ...... ii
Multiply equation i by 4
Multiply equation ii by 5
20x + 32y = 72 ...... iii
20x + 30y = 70 ...... iv
Subtract iv from iii
2y = 2
y = 2/2 = 1
Dishes cost $1
Since 5x + 8y = 18
5x + 8(1) = 18
5x = 18 - 8
5x = 10
x = 2
Laundry cost $2
tan( 20 ) + 4 Sin( 20 ) =
( Sin( 20 ) / Cos( 20 ) ) + 4 Sin( 20 ) =
Sin( 20 ) + 4 Sin( 20 ).Cos( 20 ) / Cos( 20 ) =
Sin( 20 ) + 2 × <u>2 Sin(20).Cos(20)</u>/ Cos(20) =
Sin( 20 ) + 2 × <u>Sin( 40 )</u><u> </u>/ Cos( 20 ) =
Sin( 20 ) + 2<em>Sin( 40 )</em> / Cos( 20 ) =
Sin( 20 ) + 2<em>C</em><em>o</em><em>s</em><em>(</em><em> </em><em>5</em><em>0</em><em> </em><em>)</em><em> </em>/ Cos ( 20 ) =
Sin( 20 ) + 2Cos( 20 + 30 ) / Cos( 20 ) =
________________________________
2 × Cos( 30 + 20 ) =
2 × [ Cos(30).Cos(20) - Sin(30).Sin(20) ] =
2 × [ √3/2 × Cos(20) - 1/2 × Sin(20) ] =
√3 Cos(20) - Sin(20)
_________________________________
Sin( 20 ) + <em>2Cos ( 20 + 30 ) </em>/ Cos( 20 ) =
Sin( 20 ) + <em>√</em><em>3</em><em> </em><em>C</em><em>o</em><em>s</em><em>(</em><em>2</em><em>0</em><em>)</em><em> </em><em>-</em><em> </em><em>S</em><em>i</em><em>n</em><em>(</em><em>2</em><em>0</em><em>)</em><em> </em>/ Cos(20) =
Sin(20) - Sin(20) + √3 Cos(20) / Cos(20) =
0 + √3 Cos(20) / Cos(20) =
√3 Cos(20) / Cos(20) =
Cos(20) simplifies from the numerator and denominator of fraction
√3 × 1 / 1 =
√3
And we're done ....
<em>The Nisaa Institute for Women’s Development</em>
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