The ¹H-NMR of 1-Butanol is shown below,
There are
Five signals found in the proton NMR spectrum of 1-Butanol.
A
Broad Singlet signal at ≈
4.7 ppm (Down Field = More Deshielded) is for proton directly attached to Oxygen atom.
Triplet Signal at ≈
3.65 ppm (Down Field = Deshielded) is for methylene group directly attached to Oxygen atom.
Multiplet Signal at ≈
1.6 ppm is for methylene which is present between two methylene groups. The shielding effect is increasing as moving away from Oxygen atom.
Multiplet Signal at ≈
1.4 ppm is for methylene which is present between terminal methyl and methylene groups. The shielding effect is increasing as moving away from Oxygen atom.
Triplet Signal at ≈
0.9 ppm (Up Field = Most Shielded) is for terminal methyl group attached to methylene group.
Result: Five Signals are found in the ¹H-NMR of 1-Butanol.
Answer: For a. Mass number for the particle is 0.
For b. The charge on the particle is -1.
For c. Another name for
- particle is electron.
Explanation:
Beta- minus decay is the decay process in which beta-particle is emitted. The mass number of the nuclei remains same and the mass number of the particle is 0. The charge on the particle is -1 and the emitted particle is also called as electron.

For a. The mass number for the particle is 0.
For b. The charge on the particle is -1.
For c. Another name for
- particle is electron.
Answer: 0.43molO₂
Explanation:
The ideal gas law for moles is
. If you did not know, R is the ideal gas constant,
.
Since the temperature must be in Kelvin, we must convert our given temperature from ℃ to K. 
Now that we have the temperature converted to Kelvin, we can plug in our information to the ideal gas law for the number of moles.



Therefore, the number of moles is 0.43molO₂.
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Answer:
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