Proton:
Positive
Found in Nucleus
Mass of 1 AMU
Neutron:
Neutral
Found in Nucleus
Mass of 1 AMU
Electron:
Negative
Found in orbitals
Mass of 0 AMU
Please mark Brainliest if this helped you! :)
50
One half-life would be
100^1/2, which would make it 50.
Nitrogen in this compound has 2 atoms. 2 multiplied by its mass, 14.007, equals 28.014. Divide 28.014 by the molar mass of calcium nitrate: 28.014/164 = 0.17081. Multiply this by 100 to achieve its percentage: 0.17081 x 100 = 17.08%
Answer:
p orbitals only
Explanation:
Carbon has an atomic number of 6 so its electron configuration will be 1s² 2s² 2p². It has two orbitals as indicated with the 2 as its period number with the outer orbital have 4 valence electrons. So carbon is in the p-orbital, period 2 and in group 4.
