Yes, an OH group from ethanol can form a hydrogen bond to the ether O atom in the same way as it can do so with the single-bonded O atom in the ester.
The O atom in the carbonyl group of the ester can also form H-bonds with ethanol.
Answer:
yes it can λ =265 nm
Explanation:
Here we will use the relationship
E = h c/λ ∴ λ = E/ hc where
h= Plank's constant
c= Speed of light
λ = Wavelength = ?
Substituting
note need E in J ,
E = 4.7 eV x 1.602 x 10⁻¹⁹ J/eV = 7.5 x 10⁻¹⁹ J)
λ = 7.5 x 10 ⁻¹⁹ J / ( 6.626 x 10⁻³⁴ Js x 3 x 10^8) = 2.65 x 10⁻⁷ m = 2.65
= 2.65 x 10⁻⁷ m x 1 x 10⁹ nm/m = 265 nm
Answer:
7.44x10⁻³ mol/L and 744 ppm
Explanation:
Let's assume that the hardness of the water is totally from Ca⁺² ions only(the hardness is the measure of Ca⁺² and Mg⁺² ions). The titration with EDTA will form a complex. The EDTA is always in 1:1 proportion, so the number of moles of it will be the number of moles of Ca⁺², which will be the number of moles of CaCO₃.
n = 0.0124 L * 0.0300 mol/L
n = 3.72x10⁻⁴ mol
The molarity is the number of moles divided by the volume (0.05 L)
M = 3.72x10⁻⁴/0.05
M = 7.44x10⁻³ mol/L
1 part per million = 1 mg/L. The molar mass of the CaCO₃ is 100 g/mol, so the mass of it is:
m = 3.72x10⁻⁴ mol * 100 g/mol
m = 0.0372 g = 37.2 mg
Then, the ppm:
37.2/0.05 = 744 ppm
Deuterium also called heavy hydrogen, isotope of hydrogen with a nucleus consisting of one proton and one neutron, which is double the mass of the nucleus of ordinary hydrogen (one proton).
The deuterium atom is widely used in prototype fusion reactors.
