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Triss [41]
3 years ago
6

Which natural occurrence is shown ? Check all that apply.

Chemistry
2 answers:
viktelen [127]3 years ago
4 0

Answer:

2. flooding

4. short-term change

Explanation:

just did the test

inysia [295]3 years ago
4 0

Answer:

2. Flooding

4. Short term environmental change

Explanation:

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NaCl + H2O → NaOH + Cl2 + H2 How many grams of chlorine gas, Cl2 are given off if 7.5 grams of sodium chloride, NaCl, are decomp
german
Yes BC ther is a equal amount of sodiam
3 0
3 years ago
I In a smaller room, such as a bathroom, the reflected sound can reverberate (echo in many directions) off the smooth tile. Why
AVprozaik [17]

Answer:

See explanation

Explanation:

It is common knowledge that quite a number of people enjoy singing in the shower. There are reasons for this!

In the shower, there are many surfaces that reflect the sound of your voice as you sing. That makes your voice to sound more powerful and have more  volume.

The reverberation of the sound makes the sound of your voice stronger and more intense altogether enriching the music produced as you sing.

5 0
3 years ago
A student sets up the following equation to convert a measurement.
Sholpan [36]

Answer:

–0.13 Pa.m²

Explanation:

From the question given above, the following data were obtained:

Measurement (Pa.mm²) = –1.3×10⁵ Pa.mm²

Measurement (Pa.m²) =?

We can convert from Pa.mm² to Pa.m² by doing the following:

1 Pa.mm² = 1×10¯⁶ Pa.m²

Therefore,

–1.3×10⁵ Pa.mm² = –1.3×10⁵ Pa.mm² × 1×10¯⁶ Pa.m² / 1 Pa.mm²

–1.3×10⁵ Pa.mm² = –0.13 Pa.m²

Thus, –1.3×10⁵ Pa.mm² is equivalent to –0.13 Pa.m².

6 0
3 years ago
In which situation would the gravitational potential energy between you and earth be greatest?
liraira [26]
Potential energy increases with increase in height as in P.E = mgh so as he runs up, their is more force trying to take it down to a lower ground.
3 0
4 years ago
Explain why a solution that is 1.3 M HF and 1.3 mM KF is not a good buffer. HF is a strong acid and cannot be used in a buffer s
zavuch27 [327]

Answer:

The ratio of acid to conjugate base is outside the buffer range of 10:1.

Explanation:

The Henderson-Hasselbalch equation for a buffer is

\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}

A buffer should have

\dfrac{1}{10} \leq \dfrac{\text{[A$^{-}]$}}{\text{[HA]}} \leq \dfrac{10}{1}

For a solution that is 1.3 mol·L⁻¹ in HF and 1.3 mmol·L⁻¹ in KF, the ratio is

\dfrac{1.3 \times 10^{-3} }{1.3} = \dfrac{1}{1000}

The ratio of acid to conjugate base is 1000:1, which is outside the range of 10:1.

A is wrong. NF is a weak acid.

C is wrong. The two species are a conjugate acid-base pair.

D is wrong. Salts of Group 1 metals are soluble.

4 0
3 years ago
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