Question

8. Sulfur has a first ionization energy of 1000 kJ/mol. Photons of what frequency are required to ionize one mole of Sulfur?​

Answer 1

Answer:

the frequency of photons $v = 1.509\times10^{39}Hz$

Explanation:

Given:  first ionization energy of 1000 kJ/mol.

No. of moles of sulfur = 1 mole

$\Delta E_1 = 1000KJ/mol$

We know that plank's constant

$h = 6.626\times10^{-34} Js$

Let the frequency of photons be ν

Also we know that ΔE = hν

this implies ν = ΔE/h

$= \frac{10^6J}{6.626\times10^{-34} Js}$

$v = 1.509\times10^{39}Hz$

Hence, the frequency of photons $v = 1.509\times10^{39}Hz$