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Assoli18 [71]
2 years ago
15

What is the y intercept of the function f(x)=2 x 3^x

Mathematics
1 answer:
Lelechka [254]2 years ago
5 0

Answer:

(0,2)

Step-by-step explanation:

by substituting 0 for x you can find the y-intercept

f(x)=2*3^x

f(x)=2*3^0

f(x)=2*1

f(x)=2

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What is the answer (algebra) <br> -(4x + 3x) = 10x - 5
MariettaO [177]

Step-by-step explanation:

-(4x + 3x) = 10x - 5

We would have to multiply the -1 by the 4x and the 3x which is in the bracket.

Though there is no 1 behind the bracket but, behind any bracket there is 1 there even though it's ignored.

So when we multiply -1 by 4x we are going to get;

-4x

And when we multiply -1 by 3x It's going to be;

-3x

We have -3 and -4 because whenever we multiply any positive and negative number the product is negative.

So;

-4x - 3x = 10x - 5

So now, we group like terms;

- 4x - 3x - 10x = -5

So now that we have grouped, we have to add the negative numbers even though there is no addition sign there we would have to add

-17x = -5

So now we divide both sides by;

-17

Which is going to be;

x=

\frac{5}{17}

5 0
3 years ago
Determine the correct set up for solving the equation using the<br> quadratic formula 4x^2-5=3x+4
slava [35]

You need to subtract everything to the left side and set it equal to zero. Combine like terms.

Then, the coefficient of x^2 is a, the coefficient of x is b, and the constant term is c.

4x^2 - 5 = 3x + 4

4x^2 - 3x - 5 - 4 = 0

4x^2 - 3x - 9 = 0

a = 4; b = -3; c = -9

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

x = \dfrac{-(-3) \pm \sqrt{(-3)^2 - 4(4)(-9)}}{2(4)}

7 0
3 years ago
How is the water molecule different from the oxygen and hydrogen molecules
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4 0
3 years ago
The maximum value of 12 sin 0-9 sin²0 is: -​
jeka57 [31]

Answer:

4

Step-by-step explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

However, I will assume you meant the angle to be \theta rather than 0 which makes sense and proceed accordingly

We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is

f(\theta) = 12sin(\theta) - 9 sin^2(\theta)

Taking the first derivative of this with respect to \theta and setting it equal to 0 lets us solve for the maximum (or minimum) value

The first derivative of f(\theta) w.r.t \theta is

                        12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right)

And setting this = 0 gives

12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right) = 0

Eliminating cos(\theta) on both sides and solving for sin(\theta) gives us

sin(\theta) = \frac{12}{18} = \frac{2}{3}

Plugging this value of sin(\theta) into the original equation gives us

12(\frac{2}{3}) - 9(\frac{4}{9} ) = 8 - 4 = 4

This is the maximum value that the function can acquire. The attached graph shows this as correct

3 0
1 year ago
What is the distance of -a and a?
melamori03 [73]

Step-by-step explanation:

Distance = positive value

a + a = 2a

6 0
3 years ago
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