<h3>There are 76 nickels in jar</h3>
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "n" be the number of quarters
1 dime = $ 0.10
1 nickel = $ 0.05
There are 140 coins in the jar
Therefore,
d + n = 140
n = 140 - d ------- eqn 1
Lee has $10.20 in a jar that contains only nickels and dimes
Therefore,
0.1d + 0.05n = 10.20 -------- eqn 2
<em><u>Substitute eqn 1 in eqn 2</u></em>
0.1d + 0.05( 140 - d) = 10.20
0.1d + 7 - 0.05d = 10.20
0.05d = 3.2
Divide both sides by 0.05
d = 64
<em><u>Substitute d = 64 in eqn 1</u></em>
n = 140 - 64
n = 76
Thus there are 76 nickels in jar