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Varvara68 [4.7K]
2 years ago
15

What are the zeros of the quadratic function f(x) = 6x2 – 24x 1?

Mathematics
1 answer:
Valentin [98]2 years ago
6 0

Answer:

1

Step-by-step explanation:

im not sure but I think it's 1

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A bowl contains 4 tangerines and 5 clementines. John randomly selects one piece of fruit, and then Pam randomly selects one of t
andre [41]

Answer:

5/18

Step-by-step explanation:

There are 9 pieces of fruit in the bowl,  tangerines and 5 clementines.

Assuming that they do not put the fruit back

P (tangerine) = number of tangerines/ total = 4/9

Then John keeps his and there are  8 pieces of fruit in the bowl,  

3 tangerines and 5 clementines.

P (Clementine) = number of clementines/ total = 5/8

P (tangerine, no replacement, Clementine) = P (tangerine) * P (Clementine)

                                                                        = 4/9 * 5/8 =5/18

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3 years ago
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Find the volume of a cube that has a side length of:<br> 6x²y5
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Answer:

Are this form 1 question

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The temperature in Antarctica during the winter can average -42.3 degrees Celsius. During the summer it can average around 11.52
Sindrei [870]

Answer:

-30.78!

Step-by-step explanation:

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2 years ago
The sum of 6 consecutive even numbers is 126.<br> What is the fourth number in this sequence?
lilavasa [31]

Answer:

The 6 numbers are: 16, 18, 20, 22, 24, and 26 so the answer would be 22.

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3 years ago
Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v
Veronika [31]

Answer:

\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = \$71  

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

 s = \$ 22.35

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and t_{\alpha/2} is the t-score corresponding to a 95% confidence level.

The t-score is given by is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 20 - 1 = 19

From the t-table at α = 0.025 and DoF = 19

t-score = 2.093

So, the margin of error is

MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\

So the required 95% confidence interval is

\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

7 0
2 years ago
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