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sergiy2304 [10]
2 years ago
8

Angie, brad, and carlos are discussing a physics problem in which two identical bullets are fired with equal speeds at equal-mas

s wood and steel blocks resting on a frictionless table. One bullet bounces off the steel block while the second becomes embedded in the wood block. All the masses and speeds are the same, says angie, so i think the blocks will have equal speeds after the collisions. But what about momentum? asks brad. The bullet hitting the wood block transfers all its momentum and energy to the block, so the wood block should end up going faster than the steel block. I think the bounce is an important factor, replies carlos. The steel block will be faster because the bullet bounces off it and goes back the other direction.
Physics
1 answer:
strojnjashka [21]2 years ago
8 0

Answer:

Momentum must be conserved in the collision.

The steel block must move faster after the collision to preserve momentum.

If the steel block is moving faster it will aso have more kinetic energy.

(Note; If the bullet hits the steel block it will have some momentum in the reverse direction and thus have a greater change in total momtntum than the bullet that becomes imbedded in the wood block)

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A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. The number zero is above the red tick mark
Digiron [165]

Answer:

16 cm

Explanation:

Given that,

The object begins from 0 and moves 3cm towards left side followed by 7 cm towards the right and then, 6 cm towards the left side.

Let the x-axis to be the +ve and on the right side and -ve on the left

Thus, displacement would be:

= 0 -3 + 7 -6

= -2 cm

This implies that the object displaces 2cm towards the left.

While the total distance covered by the object equal to,

= 0cm + 3cm + 7cm + 6cm

= 16 cm

Thus, <u>16 cm</u> is the total distance.

3 0
3 years ago
What accounts for the two precipitation peaks in mbandaka?
slava [35]

The two precipitation peaks in Mbandaka during March to April and September to November is due to the intertropical convergence zone.

Intertropical convergence zone is a narrow zone located near the equator. It is where the northern and southern air masses intersect which results to low atmospheric pressure. Due to the intertropical convergence zone’s meeting of air masses, often times the air pressure are lower which will results to colder air, or even rainfall during the period of March to April, and most especially September to November in Mbandaka.

<span>Since Mbandaka is located at the cented of Tumba-Ngiri-Maindombe area, which is named as a Wetland of International importance, there is really a bigger chance that this place experience above 60mm precipitation in a year, temperatures averaging from 23 – 26 degrees Celsius.</span>

7 0
3 years ago
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tankabanditka [31]
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3 0
3 years ago
Currently, is our planet an open or closed system?
Dmitrij [34]
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8 0
3 years ago
Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road oriented at an angle of 25
Sveta_85 [38]

Answer:

8.6 miles

Explanation:

We need to calculate the components of the total displacement along the east-west and north-south directions first.

In the first part, Erica moves 5.2 miles at 25∘ north of east. So the components of this displacement along the two directions are:

East: d_{1x} = 5.2 cos 25^{\circ}=4.7 mi

North: d_{1y} = 5.2 sin 25^{\circ}=2.2 mi

In the second part, Erica moves 5.0 miles north. So, the components of this displacement are:

East: d_{2x}=0

North: d_{2y} = 5.0 mi

So the components of the total displacement are

East: d_x = d_{1x}+d_{2x}=4.7 + 0 = 4.7 mi

North: d_y = d_{1y}+d_{2y}= 2.2 + 5.0 = 7.2 mi

Therefore the magnitude of the displacement, which is the straight-line distance from the starting point to the end of the race, is

d=\sqrt{d_x^2 +d_y^2}=\sqrt{4.7^2+7.2^2}=8.6 mi

5 0
4 years ago
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