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Elenna [48]
3 years ago
10

A person stands 6.00 m from a speaker and 8.00 m from an identical speaker. What is the frequency of the second (n=2) interferen

ce minimum (destructive)? (unit=Hz)?
Physics
1 answer:
sergey [27]3 years ago
4 0

distance from speaker = r1 = 6 m

distance from identical speaker = r2 = 8m

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If you and a friend are standing at opposites ends of a gymnasium and one of you claps, will the other hear the clap at the same
34kurt

Answer:

No. Your friend will not hear the clap when he/she sees it.

Explanation:

It takes time for sound waves to go through a large area. It takes longer if people are in the area rather than it is empty.

3 0
3 years ago
A mass of 4.8 kg is dropped from a height of 4.84 meters above a vertical spring anchored at its lower end to the floor. If the
krek1111 [17]

Answer:

45.6 cm

Explanation:

Let x (m) be the length that the spring is compressed. We know that when we drop the mass from 4.84 m above and compress the springi, ts gravitational energy shall be converted to spring potential energy due to the law of energy conservation

E_g = E_p

mgh = 0.5kx^2

where h = 4.84 + x is the distance from the dropping point the the compressed point, and k = 24N/cm = 2400N/m is the spring constant, g = 9.81 m/s2 is the gravitational acceleration constant. And m = 4.8 kg is the object mass.

4.8*9.81(4.84 + x) = 0.5 * 2400 * x^2

47.088x + 227.906 = 1200x^2

1200x^2 - 47.088x - 227.906 = 0

x = 0.456m or 45.6 cm

5 0
4 years ago
An object is falling toward Earth's surface, and its acceleration due to gravity is measured. What is NOT needed to calculate Ea
mario62 [17]

I think it's weight of the object.

7 0
3 years ago
An object is located 50 cm from a converging lens having a focal length of 15 cm. Which of the following is true regarding the i
Diano4ka-milaya [45]

Answer:

It is real, inverted, and smaller than the object.

Explanation:

First of all, we can use the lens equation to find the location of the image:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

q is the distance of the image from the lens

f = 15 cm is the focal length (positive for a converging lens)

p = 50 cm is the distance of the object from the lens

Solving the equation for q,

\frac{1}{q}=\frac{1}{15 cm}-\frac{1}{50 cm}=0.047 cm^{-1}\\q=\frac{1}{0.047 cm^{-1}}=21.3 cm

The distance of the image from the lens is positive, so we can already conclude that the image is real.

Now we can also write the magnification equation:

{h_i}=-h_o \frac{q}{p}

where h_i, h_o are the size of the image and of the object, respectively.

Substituting p = 50 cm and q = 21.3 cm, we have

{h_i}=-h_o \frac{21.3 cm}{50 cm}=-0.43 h_o

So from this relationship we observe that:

|h_i| < |h_o| --> this means that the image is smaller than the object, and

h_i < 0 --> this means that the image is inverted

so, the correct answer is

It is real, inverted, and smaller than the object.

4 0
3 years ago
Oxygen is needed by all cells of most organisms for the release of
pashok25 [27]

Answer:

From the SUN

Explanation:

Hope it helps!!!

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7 0
2 years ago
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