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Elenna [48]
2 years ago
10

A person stands 6.00 m from a speaker and 8.00 m from an identical speaker. What is the frequency of the second (n=2) interferen

ce minimum (destructive)? (unit=Hz)?
Physics
1 answer:
sergey [27]2 years ago
4 0

distance from speaker = r1 = 6 m

distance from identical speaker = r2 = 8m

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The opening to a cave is a tall, 30-cm-wide crack. A bat that is preparing to leave the cave emits a 30 kHz ultrasonic chirp. Ho
sweet-ann [11.9K]

Answer:

Width of sound beam is 7.557 m

Explanation:

First we will calculate the wave length from given data:

λ=v/f

Were:

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f is the frequency

\lambda=\frac{340}{30*10^3}\\ \lambda=0.01133 m

We considered the opening long and narrow, Using single slit diffraction formula:

mλ=dsinΘ

where:

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m is the order

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Considering m=1, The angle between first minimum from center of beam is:

\theta=sin^{-1}(\frac{m\lambda}{d})\\\theta=sin^{-1}(\frac{1*0.01133}{30*10^{-2}})\\ \theta=2.164^o

The width of beam is:

tanΘ=y/L

tan\theta=\frac{w/2}{L}\\ w=2L\ tan\theta\\w=2*100*tan 2.164\\w=7.557 m

Width=7.557 m

5 0
2 years ago
Why is it difficult to convert miles to yards
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There's really no "why", because it's not difficult at all.
 
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6 0
3 years ago
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A manufacturer sells two goods, one at a price of $1000 a unit and the other at a price of $16,500 a unit. A quantity q1 of the
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Answer:

manufacturing cost = $16.5 q₂ + $1 q₁ - $ 5

Explanation:

given,

one unit price of  first good is = $ 1000

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quantity of the first good = q₁

quantity of the second good = q₂                      

total cost to the manufacturer =  $ 5000

revenue from  good one = $1000 q₁                    

revenue from second good = $16500 q₂                      

manufacturing cost = total revenue - total manufacturing cost

manufacturing cost = $16500 q₂ + $1000 q₁ - $ 5000        

but in the question we have to answer in thousands of dollar

so, divide the result by 1000                  

manufacturing cost = $16.5 q₂ + $1 q₁ - $ 5                

4 0
3 years ago
A 10.00-V battery is connected between two parallel metal plates 4.00 mm apart. What is the magnitude of the electric field betw
olya-2409 [2.1K]

Answer:

2500 N/C

Explanation:

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Substitute into equation 2

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Hence the electric field = 2500 N/C

6 0
3 years ago
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