All categories

3 years ago

In the equation for the gravitational force between two objects, which quantity must be squared?

Physics

2 answers:

timama [110]3 years ago

4 0

Answer: The distance between the objects.

Explanation: The equation for the gravitational force is written as:

F = G*m1*m2/r^2

Where r is the distance between the objects, m1 and m2 are the masses and G is the gravitational constant.

This cuantity is in the denominator because, as larger is the distance, smaller is the strenght of the field.

And is squared because is a force that spreads in a solid angle (as the change of area in a growing sphere )

Trava [24]3 years ago

3 0

The distance quantity/ measurement must be squared.

You might be interested in

What is the answer to this question?

solmaris [256]

Answer:

NA2SO3 is the reactant in the reaction

Explanation:

The substances which take part in a chemical reaction are called reactants

HOPE IT HELPS 

HAVE A NICE DAY :)

XxYourBabyGirlxX2

8 0

2 years ago

Convert 9.75 millimeters to centimeter

Butoxors [25]

Answer:

0.975cm

Explanation:

7 0

3 years ago

Read 2 more answers

11. You want to calculate the displacement of an object thrown over a bridge. Using -10 m/s2 for acceleration due to gravity, wh

IrinaVladis [17]

Answer:

The displacement was 320 meters.

Explanation:

Assuming projectile motion and zero initial speed (i.e., the object was dropped, not thrown down), you can calculate the displacement using the kinematic equation:

$d = \frac{1}{2}gt^2=\frac{1}{2}10\frac{m}{s^2}\cdot 8^2 s^2=320 m$

The displacement was 320 meters.

7 0

3 years ago

PSYW - Please Show Your Work

Ad libitum [116K]

Answer:

9.66E4 J

Explanation:

7 0

3 years ago

Find the electric energy density between the plates of a 225-μF parallel-plate capacitor. The potential difference between the p

PSYCHO15rus [73]

Answer:

Energy density will be 14.73 $J/m^3$

Explanation:

We have given capacitance $C=225\mu F=225\times 10^{-6}F$

Potential difference between the plates = 365 V

Plate separation d = 0.200 mm $0.2\times 10^{-3}m$

We know that there is relation between electric field and potential

$E=\frac{V}{d}$ , here E is electric field, V is potential and d is separation between the plates

So $E=\frac{V}{d}=\frac{365}{0.2\times 10^{-3}}=1825000N/C$

Energy density is given by $E=\frac{1}{2}\varepsilon _0E^2=\frac{1}{2}\times 8.85\times 10^{-12}\times (1.825\times 10^6)^2=14.73J/m^3$

5 0

2 years ago

In the equation for the gravitational force between two objects, which quantity must be squared?​

In the equation for the gravitational force between two objects, which quantity must be squared?