A particle is constrained to move round a circle radius 382400km and makes a single revolution in 27.3 days. (i). Find the veloc

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3 years ago

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ity in ms-1. (ii). Find its acceleration

1 answer:

andreyandreev [35.5K] · Answer 1 · 2022-10-01T13:44:36+03:00

The velocity and acceleration of the particle moving round the circle is;

Velocity = 162.12 m/s

Velocity = 162.12 m/sAcceleration = 6.873 × 10^(-5) m/s²

We are given;

Radius of circle; 382400 km = 382400000 m

Time; t = 27.3 days = 27.3 × 86400 s = 2358720 s

Now, formula for velocity is;

Velocity = distance/time

Thus;

I) velocity = 382400000/2358720

Velocity = 162.12 m/s

II) Acceleration is centripetal acceleration and is given by the formula;

a = v²/r

a = 162.12²/382400000

a = 6.873 × 10^(-5) m/s²

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