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frutty [35]
3 years ago
7

A particle is constrained to move round a circle radius 382400km and makes a single revolution in 27.3 days. (i). Find the veloc

ity in ms-1. (ii). Find its acceleration
Physics
1 answer:
andreyandreev [35.5K]3 years ago
5 0

The velocity and acceleration of the particle moving round the circle is;

<em><u>Velocity = 162.12 m/s</u></em>

<em><u>Velocity = 162.12 m/sAcceleration = 6.873 × 10^(-5) m/s²</u></em>

We are given;

Radius of circle; 382400 km = 382400000 m

Time; t = 27.3 days = 27.3 × 86400 s = 2358720 s

Now, formula for velocity is;

Velocity = distance/time

Thus;

I) velocity = 382400000/2358720

Velocity = 162.12 m/s

II) Acceleration is centripetal acceleration and is given by the formula;

a = v²/r

a = 162.12²/382400000

a = 6.873 × 10^(-5) m/s²

Read more at; brainly.com/question/12199398

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A nickel (5 cent coin) has a mass of 5.0 g. How many nickels are there in a stack of nickels with a mass of 10.0 kg?
Marrrta [24]

Answer:

2000 nickels

Explanation:

One way to solve proportionality problems, direct and inverse: the simple 3 rule.

If the relationship between the magnitudes is direct (when one magnitude increases so does the other), the simple direct rule of three must be applied.

On the contrary, if the relationship between the magnitudes is inverse (when one magnitude increases the other decreases) the rule of three simple inverse applies.

The simple 3 rule is an operation that helps us quickly solve proportionality problems, both direct and inverse.

To make a simple rule of three we need 3 data: two magnitudes proportional to each other, and a third magnitude. From these, we will find out the fourth term of proportionality.

In the simple three rule, therefore, the proportionality relationship between two known values ​​A and B is established, and knowing a third value C, a fourth value D is calculated.

A -> B

C -> D

Calculation

1 nickel --> 5 g

X? nickel --> 10000g

X = (10000 g * 1 nickel) / 5 g

X = 2000 nickels

7 0
3 years ago
An irregular object of mass 3 kg rotates about an axis, about which it has a radius of gyration of 0.2 m, with an angular accele
Citrus2011 [14]

Answer:

The magnitude of the applied torque is 6.0\times10^{-2}\ N-m

(e) is correct option.

Explanation:

Given that,

Mass of object = 3 kg

Radius of gyration = 0.2 m

Angular acceleration = 0.5 rad/s²

We need to calculate the applied torque

Using formula of torque

\tau=I\times\alpha

Here, I = mk²

\tau=mk^2\times\alpha

Put the value into the formula

\tau=3\times(0.2)^2\times0.5

\tau=0.06\ N-m

\tau=6.0\times10^{-2}\ N-m

Hence, The magnitude of the applied torque is 6.0\times10^{-2}\ N-m

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_____ is a chemical property of matter.
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Answer:

it is chemical reactivity (D)

Explanation:

it is because chemical properties are properties that can be measured and observed only when matter undergoes a change to become an entirely different kind of matter.Which they include Chemical reactivity,flammable,and the ability to rust.And Chemical reactivity is the ability of matter to react chemically with other substances.

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Which of the following are properties of mechanical waves?
yuradex [85]

The properties of mechanical waves are : ( C and D )

  • The three categories of mechanical waves are transverse, longitudinal,surface waves ( C )
  • Waves transport energy,but not matter ( D )

<h3>What are mechanical waves ?</h3>

Mechanical waves are a category of waves which cannot transmit energy through a vacuum, i.e. they require a medium to transmit their energy from one end to another. An example of a mechanical wave is : sound wave. Mechanical waves are grouped into transverse, longitudinal and surface waves.

Hence we can conclude that The properties of mechanical waves are : The three categories of mechanical waves are transverse, longitudinal,surface waves and Waves transport energy,but not matter

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