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MissTica
4 years ago
12

If 3lbs costs 4.00$ how much will 2 lbs cost

Mathematics
2 answers:
Crank4 years ago
8 0
It will cost for 2 lbs it is 1.5
harkovskaia [24]4 years ago
3 0

Answer:

1.5

Step-by-step explanation:

if you do 3 divided by 4 then you get 0.75 then you have to do 0.75 times 2 and you get 1.5 dollars for 2 pounds

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A baking company charges $1.75 per slice of cake for baking and $0.35 per slice for decorating. How much would a decorated cake
tiny-mole [99]
It will be a total of $315
8 0
4 years ago
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HiCan you please state the Pythagorean TheoremVerbally and algebraically
Natalija [7]
Pythagorean Theorem<h2>Verbally:</h2>

Let's say a and b are the legs, and c is the hypotenuse. Then, algebraically, the theorem is,

a^2+b^2=c^2

7 0
2 years ago
In a survey, 27 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped
tatiyna

Answer: (29.4, 32.6)

Step-by-step explanation:

From the question, we know that

Sample size (n) = 27

Sample mean (x) = $31

Sample standard deviation (s) = $3

We are to construct a 99% confidence interval interval for average amount spent on gift.

The formulae for constructing a 99% confidence interval for population mean is given as

u = x + tα/2 × s/√n...... For upper limit

u = x - tα/2 × s/√n...... For lower limit

tα/2 is the critical value for a 2 tailed test. This value of gotten from a t distribution table by checking the degree of freedom ( 27 - 1 = 26) against the level of significance ( 100% - 99% = 1%).

Hence tα/2 = 2.779

Let us substitute our parameters and solve

For lower limit

u = 31 - 2.779 × 3/√27

u = 31 - 2.779 ( 0.5773)

u = 31 - 1.6045

u = 29.4

For upper limit

u = 31 + 2.779 × 3/√27

u = 31 + 2.779 ( 0.5773)

u = 31 + 1.6045

u = 32.6

Hence the 99% confidence interval for population mean is given as 29.4, 32.6

6 0
3 years ago
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Which transformations are needed to change the parent cosine function to the cosine function below?
Otrada [13]

Question:

1. vertical stretch of 2, horizontal stretch to a period of 2 pi, phase shift of StartFraction pi Over 2 EndFraction units to the right, vertical shift of 1 unit up

2. vertical compression of 2, horizontal stretch to a period of StartFraction pi Over 4 EndFraction, phase shift of StartFraction pi Over 4 EndFraction units to the left, vertical shift of 2 units down

3. vertical compression of 2, horizontal compression to a period of 4 pi, phase shift of StartFraction pi Over 3 EndFraction units to the left, vertical shift of 1 unit down

4. vertical stretch of 2, horizontal compression to a period of StartFraction pi Over 2 EndFraction, phase shift of Pi units to the right, vertical shift of 1 unit down

Answer:

The correct option is;

4. Vertical stretch of 2, horizontal compression to a period of π/2, phase shift of π units to the right, vertical shift of 1 unit down

Step-by-step explanation:

Here, we have the parent cosine function given by y = cos(x)

A plot of the above function is attached

By comparison, it is observed that the transformation required to change the parent function includes;

1. Vertical stretch from the parent function of amplitude 1 to amplitude 2

2. A horizontal compression so that the period of one complete revolution is π/2 rather than 2·π in the parent cosine function

3. Phase shift of pi units to the right such that cos(π) = 1 rather than cos(2π) = 1 as it applies to the parent function

4. Shift of the y values from the symmetrical x-axis origin downwards by 1 unit such that the maximum y value of the doubly stretched transformation is 1 rather than 2

5 0
4 years ago
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Which polynomial is prime?<br><br> x2 – 36<br> x2 + 16<br> x2 – 7x + 12<br> x2 – x – 20
juin [17]

Answer:

x2 - 7x + 12

Step-by-step explanation:

ℎ

3 0
3 years ago
Read 2 more answers
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