Answer:
a = 629
Step-by-step explanation:
a = w * L
w = 17
L = 2w + 3
a = (17) * (2w + 3)
a = (17) * (2(17) + 3)
a = 17 * (34 + 3)
a = 17 * (37)
a = 629
keeping in mind that when the logarithm base is omitted, the base 10 is assumed.
![\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x](https://tex.z-dn.net/?f=%5Ctextit%7Bexponential%20form%20of%20a%20logarithm%7D%20%5C%5C%5C%5C%20%5Clog_a%28b%29%3Dy%20%5Cqquad%20%5Cimplies%20%5Cqquad%20a%5Ey%3D%20b%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Clog%28x%29%3D2%5Cimplies%20%5Clog_%7B10%7D%28x%29%3D2%5Cimplies%2010%5E2%3Dx%5Cimplies%20100%3Dx)
First, let's re-arrange to slope-intercept form.
x + 8y = 27
Subtract 'x' to both sides:
8y = -x + 27
Divide 8 to both sides:
y = -1/8x + 3.375
So the slope of this line is -1/8, to find the slope that is perpendicular to this, we multiply it by -1 and flip it. -1/8 * -1 = 1/8, flipping it will give us 8/1 or 8.
So the slope of the perpendicular line will be 8.
Now we can plug this into point-slope form along with the point given.
y - y1 = m(x - x1)
y - 5 = 8(x + 5)
y - 5 = 8x + 40
y = 8x + 45
OK so you have 250 skittles. But you only pull out 25. You pull out 5 red skittles, 7 yellow skittles,8 orange skittles,2 green skittles and 3 purple skittles. So how many red skittles are in the whole box. The way i would look at it is theres 5 red skittles in every 25 skittles. So whats 250 divided by 25 that would be 10. So you can imagine you have 10 groups of skittles. In each group theres 5 skittles. So all together there would be 50 red skittles. Sooo based on the infromation there would be 50 red skittles expected in the box. I hope this helped pls mark me as brainliest!!
First, pull out the GCM from the two terms: 3x^6(x^3-64)
Then factor the remains using the difference of cubes: 3x^6(x-4)(x^2+4x+16)
