Answer: D) csc (2π/3)
<u>Step-by-step explanation:</u>
2π/3 is in Quadrant II
Quadrant II has a negative x-value and a positive y-value.
x-values are: cos & sec
y-values are: sin & csc
tan = y/x so will be negative in Quadrant II
A) sec = -
B) tan = -
C) cos = -
D) csc = + this works!
Answer:
The third side must be 10: {3, 10, 10}; {10, 3, 3} is not possible.
Step-by-step explanation:
Everything depends on our understanding of "isosceles."
This term indicates that two sides of a given triangle are equal.
If two sides of an isosceles triangle have lengths of 3 and 10, then:
Either 1) Two sides have length 10 and the third side has length 3. This is certainly possible
or
2) sides have length 3 and the third side has length 10. This is NOT possible, since 3 + 3 adds up to 6, which is less than 10.
Hello from MrBillDoesMath!
Answer:
108 cm^2
Discussion:
The area of the logo =
area of Trapezoid on top (I) + area of triangle on bottom (II)
I = (1/2) h ( b1 + b2) h = altitude, b1, b2 = bases
= (1/2) 6 ( 6 + 12)
= (1/2) 6 ( 18)
= 54
II = (1/2) b h
= (1/2) (12) ( 15 - 6) => altitude of triangle = 15 - 6 NOT (1/2) 15
= 54
I + II= 54 + 54 = 108
Thank you,
MrB
Answer:
$34.50 saved
Step-by-step explanation:
230 - 15% = $195.5
230 - 195.5 = 34.5 saved
