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Vlad [161]
3 years ago
9

jim weighs more than joe but less than jack. Their weights in kilograms are consecutive by multiples of 7. If they each weighed

5kg less, the sum of their weights is 195kg
Mathematics
1 answer:
In-s [12.5K]3 years ago
8 0

Joe: 7k

Jim: 7(k+1)

Jack: 7(k+2)

(7k-5) + (7(k+1) - 5) + (7(k+2) - 5) = 195

(7k-5) + (7k+2) + (7k +9) = 195

21k + 6 = 195

21k = 189

k = 9

Joe: 7k = 7(9) = 63

Jim: 7(k+1) = 7(9+1) = 7(10) = 70

Jack: 7(k+2) = 7(9+2) = 7(11) = 77

Answer: Joe=63kg, Jim=70kg, Jack=77kg

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The answer to your question is the letter A.

Step-by-step explanation:

Data

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Process

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