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Vlad [161]
3 years ago
9

jim weighs more than joe but less than jack. Their weights in kilograms are consecutive by multiples of 7. If they each weighed

5kg less, the sum of their weights is 195kg
Mathematics
1 answer:
In-s [12.5K]3 years ago
8 0

Joe: 7k

Jim: 7(k+1)

Jack: 7(k+2)

(7k-5) + (7(k+1) - 5) + (7(k+2) - 5) = 195

(7k-5) + (7k+2) + (7k +9) = 195

21k + 6 = 195

21k = 189

k = 9

Joe: 7k = 7(9) = 63

Jim: 7(k+1) = 7(9+1) = 7(10) = 70

Jack: 7(k+2) = 7(9+2) = 7(11) = 77

Answer: Joe=63kg, Jim=70kg, Jack=77kg

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The weight of a person on or above the surface of the earth varies inversely as the square of the distance the person is from th
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\frac{180}{Wspace} =  \frac{ \frac{k}{3900^{2} } }{ \frac{k}{4750^{2}} /[tex]\\Now you need to invert and multiply the bottom fraction on the left.\\[tex] \frac{180}{x} {=} \frac{k}{3900^{2}} {*} \frac{4750^{2}}{k} 

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4 0
3 years ago
Read 2 more answers
3 2/3 divide 1 2/7 in simplest form
I am Lyosha [343]

Answer:

2 23/27

Step-by-step explanation:

3 2/3 / 1 2/7

= 11/3 / 1 2/7

= 11/3 / 9/7

= 77/27

= 2 23/27

Hope it helped!

6 0
3 years ago
Read 2 more answers
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