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Vlad [161]
3 years ago
9

jim weighs more than joe but less than jack. Their weights in kilograms are consecutive by multiples of 7. If they each weighed

5kg less, the sum of their weights is 195kg
Mathematics
1 answer:
In-s [12.5K]3 years ago
8 0

Joe: 7k

Jim: 7(k+1)

Jack: 7(k+2)

(7k-5) + (7(k+1) - 5) + (7(k+2) - 5) = 195

(7k-5) + (7k+2) + (7k +9) = 195

21k + 6 = 195

21k = 189

k = 9

Joe: 7k = 7(9) = 63

Jim: 7(k+1) = 7(9+1) = 7(10) = 70

Jack: 7(k+2) = 7(9+2) = 7(11) = 77

Answer: Joe=63kg, Jim=70kg, Jack=77kg

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Answer:

64°

Step-by-step explanation:

First, we have to find the angle situated in R, the addition of all angles in a triangle is 180° so that means:

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x = 180-116 = 64°

Now, remember that this angle (64°) is the same as this one = ?, thanks to one property.

So basically, that angle has the same value as that one.

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Hope it was helpful ;)

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3 years ago
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Which point represents 4StartRoot 2 EndRoot (cosine (StartFraction 5 pi Over 4 EndFraction) + I sine (StartFraction 5 pi over 4
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Step-by-step explanation:

They said so, thank you.

3 0
3 years ago
O terreno da fazenda de Eduardo foi aumentado 2 m na horizontal e 2 m na vertical. Se antes do aumento o terreno tinha o formato
Novay_Z [31]

Answer:

New area of Eduardo's farm after the increase = x² + 4x + 4

Nova área da fazenda de Eduardo após o aumento = x² + 4x + 4

Step-by-step explanation:

English Translation

The land on Eduardo's farm was increased by 2 m horizontally and 2 m vertically. If before the increase the land was shaped like an x-side square, what is the new area after the increases?

Solution

The previous area of Eduardo's farm is the are of a square with side lenght of x.

Area of a square = (side length)² = x²

Then, the land on Eduardo's farm was increased by 2 m horizontally and 2 m vertically.

New horizontal length of Eduardo's farm = (x+2)

New vertical length of Eduardo's farm = (x+2)

New area of Eduardo's farm = (x+2)(x+2)

= x² + 4x + 4

In Portugese/Em português

A área anterior da fazenda de Eduardo é a de um quadrado com comprimento lateral de x.

Área de um quadrado = (comprimento lateral)² = x²

Em seguida, o terreno da fazenda de Eduardo foi aumentado 2 m na horizontal e 2 m na vertical.

Novo comprimento horizontal da fazenda de Eduardo = (x + 2)

Novo comprimento vertical da fazenda de Eduardo = (x + 2)

Nova área da fazenda de Eduardo

= (x + 2) (x + 2) = x² + 4x + 4

Hope this Helps!!!

Espero que isto ajude!!!

7 0
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