Question

The means and mean absolute deviations of sidney’s and phil’s grades are shown in the table below. means and mean absolute deviations of sidney’s and phil’s grades sidney phil mean 82 78 mean absolute deviation 3.28 3.96 which expression represents the ratio of the difference of the two means to sidney’s mean absolute deviation? startfraction 82 over 3.28 endfraction startfraction 4 over 3.28 endfraction startfraction 4 over 0.68 endfraction startfraction 82 over 0.68 endfraction

Answer 1

The expression that represents the ratio of the difference of the two means to Sidney’s mean absolute deviation is given by: Option B: 4/3.28

What is mean absolute deviation?

Mean absolute deviation is the average of the absolute deviation of each observation from their mean, for a considered set of observations.

For this case, the table of mean and mean absolute deviation is given as:

$\begin{array}{ccc}&Mean&M.A.D.\\\text{Sidney}&82&3.28\\\text{Phill}&78&3.96\end{array}$

(M.A.D refers to Mean Absolute Deviation).

So, difference in their mean is 82 - 78 = 4

Absolute deviation  for Sidney is 3.28

Thier ratio is: 4/3.28

Thus, the expression that represents the ratio of the difference of the two means to Sidney’s mean absolute deviation is given by: Option B: 4/3.28

Learn more about ratio here:

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