Use an inequality:
S = sum
7 + 7 < S < 8 + 9
14 < S < 17
so the sum is between 14 and 17
Since 2 and 11 are prime we have
(2x 1)(1x 11) or
(2x 11)(1x 1)
we just need to figure out the signs
remember
(ax+b)(cx+d)=acx^2+bcx+adx+bd
the middle term coeficient is bc+ad
so
2x times 11=22x
1x times 1=x
there is not way to add or subtract 22x and x to get -9x
1st one is wrong
(2x 11)(x 1)
2x times 1=2x
11 times x=11x
11x-2x=9x
the 2x or the 1 has to have the negative
(2x+11)(x-1)
Sin(x) = opposite over hypotenuse
Cos(x) = adjacent over hypotenuse
Tan(x) = opposite over adjacent
Everything revolves around a right triangle.
From the given equation, "<span>sine of x equals square root of 2 over 2"
Opposite = square root of 2
Hypotenuse = 2
Adjacent = ?
Using the Pythagorean Equation: H^2 = O^2 + A^2
2^2 = (square root of 2)^2 + A^2
A^2 = 4 - 2
A = square root of 2
Cos(x) = square root of 2 over 2
Tan(x) = square root of 2 over square root of 2 = 1</span>
Yes, it is also a square number
18, I believe 360/20 equals 18.
