I’m trying to work it out right now but either way search it up it might come out
This website has a calculator that also has step-by-step explanations. https://www.mathpapa.com/algebra-calculator.html
Answer:
a)148.47
b)148.34
Step-by-step explanation:
Let π(x) be the prime-counting function that gives the number of primes less than or equal to x, for any real number x. For example, π(7) = 4 because there are four prime numbers (2, 3, 5, 7) less than or equal to 7.
We can see that π(7)=π(10) because there are four prime numbers (2,3,5,7) less than or equal to 10.
A good aproximation for π(x) is x / log x, where log x is the natural logarithm of x.
a)The number of primes between 1 and 1030.
1030/log(1030)=148.47
b) The number of primes between 1 and 1029.
1029/log(1029)=148.34
Extra: π(1029)=π(1030) because 1030 is not a prime.
I believe “NK” is not a line segment
Okay, so this is just a basic multiplication problem. first, we need to divide to figure out how much the trout population grows after 1 year. If it doubles in 4 years, then it will rise by a quarter each single year. So to put that in terms of fractions, then for every year, the equation would be 250x1/4. So then we do the equation, coming up with 62.5. This means that the population rises roughly 63 fish a year. So after 1 year, you will have roughly 313 fish. (312.5 to be exact). Then to get that by ten years, we can just multiply the number that we got for one year by ten. 62.5x10=625. So then we add the 250 original trout, and 250+625=875. So after 10 years, there will be 875 trout.
