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2 years ago

Please answer asap brainset

Mathematics

1 answer:

drek231 [11]2 years ago

4 0

Answer:

9 and 3

Step-by-step explanation:

9 feet. 12 inches = 1 foot. 3 feet = 1 yard.

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24g+40f this confusing

valina [46]

Answer:

Step-by-step explanation: because 24g reverts 40f so we have to subtract them

and get the answer

5 0

2 years ago

2 circles labeled Set A and Set B overlap. Set A contains 1, set B contains 3, and the overlap of the 2 circles contains 2. The

mezya [45]

The region(s) represent the intersection of Set A and Set B (A∩B) is region II

<h3>How to determine which region(s) represent the intersection of Set A and Set B (A∩B)?</h3>

The complete question is added as an attachment

The universal set is given as:

Set U

While the subsets are:

Set A
Set B

The intersection of set A and set B is the region that is common in set A and set B

From the attached figure, we have the region that is common in set A and set B to be region II

This means that

The intersection of set A and set B is the region II

Hence, the region(s) represent the intersection of Set A and Set B (A∩B) is region II

Read more about sets at:

brainly.com/question/24713052

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8 0

1 year ago

100 x 100 uygjfdis9iiugjnjjbjf

Maslowich

✨10,000 I want a pickle✨

6 0

2 years ago

Read 2 more answers

Bennett displays his basketball jersey in a rectangular prism shaped glass case. The case has a length of 18 in, a width of 3.5

Crank

Multiply your numbers together

7 0

2 years ago

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

4 0

2 years ago