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Andrews [41]
2 years ago
7

Determine a series of transformations that would map polygon ABCDE onto polygon A'B'C'D'E'?

Mathematics
1 answer:
Anvisha [2.4K]2 years ago
3 0

Answer:

Dilate by a scale factor of 0.5 with the origin as the center of dilation.

Rotate 90° clockwise about the origin

Step-by-step explanation:

Polygon ABCD:

  • A = (-2, 4)
  • B = (-8, 2)
  • C = (-4, 8)
  • D = (-2, 6)

Dilate by a scale factor of 0.5 with the origin as the center of dilation (pink polygon on attached diagram).

This means multiply the x and y values of the points by 0.5:

A → (-1, 2)

B → (-4, 1)

C → (-2, 4)

D → (-1, 3)

Rotate 90° clockwise about the origin: (x, y) → (-y, x)

A' = (-2, 1)

B' = (-1, 4)

C' = (-4, 2)

D' = (-3, 1)

So the transformations are:

  • Dilate by a scale factor of 0.5 with the origin as the center of dilation.
  • Rotate 90° clockwise about the origin.

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y = \frac{1}{2} x + 2.

Step-by-step explanation:

From the given table it is clear that x and y are linearly related.

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The first two given points are (2,3), and (4,4).

Therefore, the equation is \frac{y - 4}{4 - 3} = \frac{x - 4}{4 - 2}

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What’s this problem
Bezzdna [24]

Answer:

use FOIL- Firsts Outsides Insides Lasts

  1. Multiply the -4 and -3 as they are the first numbers of each brackets -4x-3=12
  2. Next the outsides so -4x6i as they are on the outskirts of each brackets -4x6i= -24i
  3. Insides so 3i and -3 as they are in the centre of the two brackets 3ix-3= -9i
  4. Lasts so 3i and 6i as they are at the end of each bracket 3ix6i=18i^2 ( i squared)
  5. add the answers together - 12+-24i+-9i+18i^2= 12-24i-9i+18i^2
  6. Simplify by adding like terms which is -24i and -9i.
<h3>12+-33i+18i^2 is the answer </h3>

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